本文整理汇总了C++中MDagPath::pathCount方法的典型用法代码示例。如果您正苦于以下问题：C++ MDagPath::pathCount方法的具体用法？C++ MDagPath::pathCount怎么用？C++ MDagPath::pathCount使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类MDagPath的用法示例。
在下文中一共展示了MDagPath::pathCount方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: writeDagNodes
void maTranslator::writeDagNodes(fstream& f)
{
fParentingRequired.clear();
MItDag dagIter;
dagIter.traverseUnderWorld(true);
MDagPath worldPath;
dagIter.getPath(worldPath);
//
// We step over the world node before starting the loop, because it
// doesn't get written out.
//
for (dagIter.next(); !dagIter.isDone(); dagIter.next())
{
MDagPath path;
dagIter.getPath(path);
//
// If the node has already been written, then all of its descendants
// must have been written, or at least checked, as well, so prune
// this branch of the tree from the iteration.
//
MFnDagNode dagNodeFn(path);
if (dagNodeFn.isFlagSet(fCreateFlag))
{
dagIter.prune();
continue;
}
//
// If this is a default node, it will be written out later, so skip
// it.
//
if (dagNodeFn.isDefaultNode()) continue;
//
// If this node is not writable, and is not a shared node, then mark
// it as having been written, and skip it.
//
if (!dagNodeFn.canBeWritten() && !dagNodeFn.isShared())
{
dagNodeFn.setFlag(fCreateFlag, true);
continue;
}
unsigned int numParents = dagNodeFn.parentCount();
if (dagNodeFn.isFromReferencedFile())
{
//
// We don't issue 'creatNode' commands for nodes from referenced
// files, but if the node has any parents which are not from
// referenced files, other than the world, then make a note that
// we'll need to issue extra 'parent' commands for it later on.
//
unsigned int i;
for (i = 0; i < numParents; i++)
{
MObject altParent = dagNodeFn.parent(i);
MFnDagNode altParentFn(altParent);
if (!altParentFn.isFromReferencedFile()
&& (altParentFn.object() != worldPath.node()))
{
fParentingRequired.append(path);
break;
}
}
}
else
{
//
// Find the node's parent.
//
MDagPath parentPath = worldPath;
if (path.length() > 1)
{
//
// Get the parent's path.
//
parentPath = path;
parentPath.pop();
//
// If the parent is in the underworld, then find the closest
// ancestor which is not.
//
if (parentPath.pathCount() > 1)
{
//
// The first segment of the path contains whatever
// portion of the path exists in the world. So the closest
// worldly ancestor is simply the one at the end of that
//.........这里部分代码省略.........