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C++ LinkList::Delete方法代码示例

本文整理汇总了C++中LinkList::Delete方法的典型用法代码示例。如果您正苦于以下问题:C++ LinkList::Delete方法的具体用法?C++ LinkList::Delete怎么用?C++ LinkList::Delete使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在LinkList的用法示例。


在下文中一共展示了LinkList::Delete方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: main

int main()
{
   int a[] = {1,9,3,5,19,38,29,2,4,25,61,-1,7};
   LinkList<int>* list = new LinkList<int>(a, 13);
   list->PrintLinkList();
   int listlength = list->ListLength();
   std::cout<<"the list length is"<<listlength<<std::endl;
   int theLastElement = list->Get(13);
   assert(theLastElement == 7);
   std::cout<<"the last  element value   is"<< theLastElement << std::endl;
   std::cout<<"the values  that  the  array  contained currently display"<<std::endl;
   list->PrintLinkList();
   std::cout<<std::endl;
   std::cout<<"delete the  eigth element 2";
   std::cout<<std::endl;
   list->Delete(8);
   std::cout<<"the values  that  the  array  contained currently display"<<std::endl;
   std::cout<<"the  position of 61 is";
   std::cout<<std::endl;
   int position = list->Locate(61);
   std::cout<<std::endl;
   std::cout<<position<<std::endl;
   std::cout<<"the values  that  the  array  contained currently display"<<std::endl;
   list->PrintLinkList();
   std::cout<<std::endl;
    std::cout<<"now we add a value  at first  position"<<std::endl;
   list->Insert(1, 11111);
   std::cout<<"the values  that  the  array  contained currently display"<<std::endl;
   list->PrintLinkList();
   std::cout<<std::endl;
   list->Invert();
   std::cout<<"the  invert  array list is"<<std::endl;
   list->PrintLinkList();
}
开发者ID:zheniantoushipashi,项目名称:amazeAlgorithm,代码行数:34,代码来源:main.cpp

示例2: main

int main()
{
    LinkList<int> ll;
    cout << "Created a link list..." << endl;
    cout << "length = " << ll.Count() << endl;

    for (int i = 1; i <= 10; i++)
    {
        int val = i * 2;
        ll.Insert(val, ll.Count() + 1);
        cout << val << " inserted. length = " << ll.Count() << endl;
    }
    Display(ll);

    cout << "Reversing ..." << endl;
    ll.Reverse();
    Display(ll);

    cout << "Reversing again ..." << endl;
    ll.Reverse();
    Display(ll);

    int idx = 1;
    int val = ll.Get(idx);
    cout << "Get(" << idx << ") = " << val << "." << endl;
    idx = ll.Locate(val);
    cout << "Locate(" << val << ") = " << idx << "." << endl;
    if (idx == ll.Locate(val))
    {
        cout << val << " is at " << idx << "." << endl;
    }

    idx = 7;
    val = ll.Get(idx);
    if (idx == ll.Locate(val))
    {
        cout << val << " is at " << idx << "." << endl;
    }

    idx = ll.Count();
    val = ll.Get(idx);
    if (idx == ll.Locate(val))
    {
        cout << val << " is at " << idx << "." << endl;
    }

    val = 9999999;
    if (-1 == ll.Locate(val))
    {
        cout << "Unable to locate " << val << "." << endl;
    }

    cout << "Inserting 3 at 3 ..." << endl;
    ll.Insert(3, 3);
    Display(ll);
    cout << "Deleting 3 ..." << endl;
    ll.Delete(3);
    Display(ll);

    cout << "Inserting 0 at 1 ..." << endl;
    ll.Insert(0, 1);
    Display(ll);
    cout << "Deleting 0 ..." << endl;
    ll.Delete(1);
    Display(ll);

    cout << "Inserting 11 at 12 ..." << endl;
    ll.Insert(11, 11);
    Display(ll);
    cout << "Deleting 11 ..." << endl;
    ll.Delete(11);
    Display(ll);
    try
    {
        cout << "call LinkList<int> lla = ll ..." << endl;
        LinkList<int> lla = ll;
        cout << "lla.length = " << lla.Count() << endl;

        cout << "call LinkList<int> llb(ll) ..." << endl;
        LinkList<int> llb(ll);
        cout << "llb.length = " << llb.Count() << endl;
        llb.Insert(77, 7);
        cout << "llb.length = " << llb.Count() << endl;

        cout << "call llb = lla ..." << endl;
        llb = lla;
        cout << "llb.length = " << llb.Count() << endl;
        cout << "lla.length = " << lla.Count() << endl;

        cout << "Splitting llb ..." << endl;
        llb.Insert(88, 8);
        cout << "llb.length = " << llb.Count() << endl;
        LinkList<int> llb2 = llb.Split();
        Display(llb);
        Display(llb2);

        cout << "Splitting ll ..." << endl;
        LinkList<int> llc = ll.Split();
        Display(ll);
        Display(llc);
//.........这里部分代码省略.........
开发者ID:fanjeffrey,项目名称:axiom.master,代码行数:101,代码来源:test_linklist.cpp

示例3: paint


//.........这里部分代码省略.........
                sort.push_back(p->data);
                p = p->next;
            }
            for(j = 0; j < sort.size(); j++) //对sort中的值排序,扫描线生成时需要所有点从小到大排好
            {
                for(k = 0; k < sort.size() - 1; k++)
                {
                    if(sort[k].x > sort[k+1].x)
                        Sort(sort[k], sort[k+1]); //值交换,开头声明的Sort函数就是在这里用的
                }
            }
            p = AEL.first->next;
            j = 0;
            while(p && j < sort.size()) //将排好序的结点在放回AEL链表中
            {
                Sort(p->data, sort[j]);
                j++;
                p = p->next;
            }
            sort.clear();
        }
        
        
        //扫描线生成,核心中的核心
        p = AEL.first->next;
        if(p) //判断AEL中是否有结点
        {
            for(j = 1; j <= AEL.Length(); j++)
            {
                k = AEL.Get(j).y; //取出每个结点的y的值,判断与当前扫描线的y坐标值即i比较,判断是否已经到线段顶部
                if(k <= i) //这里我用了一个小技巧,没有按课上讲的通过端点是否为极值点来判断端点应该去还是留
                    //我用的方法是判断端点是线段起点还是终点,是起点的改点保存,是终点就delete,
                {
                    AEL.Delete(j);
                    j--;
                }
            }
            p = AEL.first;
            while(p->next) //将AEL链表中的点信息结点两两取出连线
            {
                
                p = p->next;
                q = p->next;
                k = (p->data.x + 0.5); //简单的四舍五入取整
                j = (q->data.x + 0.5);
                
                switch(Bcolor)
                {
                    case red://红
                        glColor3f(1.0,0.0,0.0);
                        glBegin(GL_LINES);
                        glVertex2i(k, i);
                        glVertex2i(j, i);
                        glEnd();
                        break;
                    case green://绿
                        glColor3f(0.0,1.0,0.0);
                        glBegin(GL_LINES);
                        glVertex2i(k, i);
                        glVertex2i(j, i);
                        glEnd();
                        break;
                    case blue://蓝
                        glColor3f(0.0,0.0,1.0);
                        glBegin(GL_LINES);
                        glVertex2i(k, i);
开发者ID:yyn835314557,项目名称:ComputerGraphics-homework,代码行数:67,代码来源:main.cpp


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