本文整理汇总了C++中LBlock::lastInstructionWithId方法的典型用法代码示例。如果您正苦于以下问题：C++ LBlock::lastInstructionWithId方法的具体用法？C++ LBlock::lastInstructionWithId怎么用？C++ LBlock::lastInstructionWithId使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类LBlock的用法示例。
在下文中一共展示了LBlock::lastInstructionWithId方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: CodePosition
bool
RegisterAllocator::init()
{
if (!insData.init(mir, graph.numInstructions()))
return false;
if (!entryPositions.reserve(graph.numBlocks()) || !exitPositions.reserve(graph.numBlocks()))
return false;
for (size_t i = 0; i < graph.numBlocks(); i++) {
LBlock* block = graph.getBlock(i);
for (LInstructionIterator ins = block->begin(); ins != block->end(); ins++)
insData[ins->id()] = *ins;
for (size_t j = 0; j < block->numPhis(); j++) {
LPhi* phi = block->getPhi(j);
insData[phi->id()] = phi;
}
CodePosition entry = block->numPhis() != 0
? CodePosition(block->getPhi(0)->id(), CodePosition::INPUT)
: inputOf(block->firstInstructionWithId());
CodePosition exit = outputOf(block->lastInstructionWithId());
MOZ_ASSERT(block->mir()->id() == i);
entryPositions.infallibleAppend(entry);
exitPositions.infallibleAppend(exit);
}
return true;
}