本文整理汇总了C++中GridPosition::namedGridLine方法的典型用法代码示例。如果您正苦于以下问题:C++ GridPosition::namedGridLine方法的具体用法?C++ GridPosition::namedGridLine怎么用?C++ GridPosition::namedGridLine使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类GridPosition
的用法示例。
在下文中一共展示了GridPosition::namedGridLine方法的10个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: resolveGridPositionFromStyle
GridResolvedPosition GridResolvedPosition::resolveGridPositionFromStyle(const RenderStyle& gridContainerStyle, const GridPosition& position, GridPositionSide side)
{
switch (position.type()) {
case ExplicitPosition: {
ASSERT(position.integerPosition());
if (!position.namedGridLine().isNull())
return resolveNamedGridLinePositionFromStyle(gridContainerStyle, position, side);
// Handle <integer> explicit position.
if (position.isPositive())
return adjustGridPositionForSide(position.integerPosition() - 1, side);
size_t resolvedPosition = abs(position.integerPosition()) - 1;
const size_t endOfTrack = explicitGridSizeForSide(gridContainerStyle, side);
// Per http://lists.w3.org/Archives/Public/www-style/2013Mar/0589.html, we clamp negative value to the first line.
if (endOfTrack < resolvedPosition)
return GridResolvedPosition(0);
return adjustGridPositionForSide(endOfTrack - resolvedPosition, side);
}
case NamedGridAreaPosition:
{
// First attempt to match the grid area’s edge to a named grid area: if there is a named line with the name
// ''<custom-ident>-start (for grid-*-start) / <custom-ident>-end'' (for grid-*-end), contributes the first such
// line to the grid item’s placement.
String namedGridLine = position.namedGridLine();
ASSERT(isValidNamedLineOrArea(namedGridLine, gridContainerStyle, side));
const NamedGridLinesMap& gridLineNames = gridLinesForSide(gridContainerStyle, side);
NamedGridLinesMap::const_iterator implicitLineIter = gridLineNames.find(implicitNamedGridLineForSide(namedGridLine, side));
if (implicitLineIter != gridLineNames.end())
return adjustGridPositionForSide(implicitLineIter->value[0], side);
// Otherwise, if there is a named line with the specified name, contributes the first such line to the grid
// item’s placement.
NamedGridLinesMap::const_iterator explicitLineIter = gridLineNames.find(namedGridLine);
if (explicitLineIter != gridLineNames.end())
return adjustGridPositionForSide(explicitLineIter->value[0], side);
// If none of the above works specs mandate us to treat it as auto BUT we should have detected it before calling
// this function in GridResolvedPosition::resolveGridPositionsFromStyle(). We should be also covered by the
// ASSERT at the beginning of this block.
ASSERT_NOT_REACHED();
return GridResolvedPosition(0);
}
case AutoPosition:
case SpanPosition:
// 'auto' and span depend on the opposite position for resolution (e.g. grid-row: auto / 1 or grid-column: span 3 / "myHeader").
ASSERT_NOT_REACHED();
return GridResolvedPosition(0);
}
ASSERT_NOT_REACHED();
return GridResolvedPosition(0);
}
示例2: resolveNamedGridLinePositionAgainstOppositePosition
static GridSpan resolveNamedGridLinePositionAgainstOppositePosition(const RenderStyle& gridContainerStyle, int oppositeLine, const GridPosition& position, GridPositionSide side, unsigned autoRepeatTracksCount)
{
ASSERT(position.isSpan());
ASSERT(!position.namedGridLine().isNull());
// Negative positions are not allowed per the specification and should have been handled during parsing.
ASSERT(position.spanPosition() > 0);
unsigned lastLine = explicitGridSizeForSide(gridContainerStyle, side, autoRepeatTracksCount);
NamedLineCollection linesCollection(gridContainerStyle, position.namedGridLine(), directionFromSide(side), lastLine, autoRepeatTracksCount);
return definiteGridSpanWithNamedLineSpanAgainstOpposite(oppositeLine, position, side, lastLine, linesCollection);
}
示例3: resolveNamedGridLinePositionFromStyle
static int resolveNamedGridLinePositionFromStyle(const RenderStyle& gridContainerStyle, const GridPosition& position, GridPositionSide side, unsigned autoRepeatTracksCount)
{
ASSERT(!position.namedGridLine().isNull());
unsigned lastLine = explicitGridSizeForSide(gridContainerStyle, side, autoRepeatTracksCount);
NamedLineCollection linesCollection(gridContainerStyle, position.namedGridLine(), directionFromSide(side), lastLine, autoRepeatTracksCount);
if (position.isPositive())
return lookAheadForNamedGridLine(0, std::abs(position.integerPosition()), lastLine, linesCollection);
return lookBackForNamedGridLine(lastLine, std::abs(position.integerPosition()), lastLine, linesCollection);
}
示例4: resolveGridPositionFromStyle
static int resolveGridPositionFromStyle(const RenderStyle& gridContainerStyle, const GridPosition& position, GridPositionSide side, unsigned autoRepeatTracksCount)
{
switch (position.type()) {
case ExplicitPosition: {
ASSERT(position.integerPosition());
if (!position.namedGridLine().isNull())
return resolveNamedGridLinePositionFromStyle(gridContainerStyle, position, side, autoRepeatTracksCount);
// Handle <integer> explicit position.
if (position.isPositive())
return position.integerPosition() - 1;
unsigned resolvedPosition = std::abs(position.integerPosition()) - 1;
const unsigned endOfTrack = explicitGridSizeForSide(gridContainerStyle, side, autoRepeatTracksCount);
return endOfTrack - resolvedPosition;
}
case NamedGridAreaPosition:
{
// First attempt to match the grid area's edge to a named grid area: if there is a named line with the name
// ''<custom-ident>-start (for grid-*-start) / <custom-ident>-end'' (for grid-*-end), contributes the first such
// line to the grid item's placement.
String namedGridLine = position.namedGridLine();
ASSERT(!position.namedGridLine().isNull());
unsigned lastLine = explicitGridSizeForSide(gridContainerStyle, side, autoRepeatTracksCount);
NamedLineCollection implicitLines(gridContainerStyle, implicitNamedGridLineForSide(namedGridLine, side), directionFromSide(side), lastLine, autoRepeatTracksCount);
if (implicitLines.hasNamedLines())
return implicitLines.firstPosition();
// Otherwise, if there is a named line with the specified name, contributes the first such line to the grid
// item's placement.
NamedLineCollection explicitLines(gridContainerStyle, namedGridLine, directionFromSide(side), lastLine, autoRepeatTracksCount);
if (explicitLines.hasNamedLines())
return explicitLines.firstPosition();
ASSERT(!NamedLineCollection::isValidNamedLineOrArea(namedGridLine, gridContainerStyle, side));
// If none of the above works specs mandate to assume that all the lines in the implicit grid have this name.
return lastLine + 1;
}
case AutoPosition:
case SpanPosition:
// 'auto' and span depend on the opposite position for resolution (e.g. grid-row: auto / 1 or grid-column: span 3 / "myHeader").
ASSERT_NOT_REACHED();
return 0;
}
ASSERT_NOT_REACHED();
return 0;
}
示例5: create
PassOwnPtr<GridSpan> GridResolvedPosition::resolveNamedGridLinePositionAgainstOppositePosition(const RenderStyle& gridContainerStyle, const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, GridPositionSide side)
{
ASSERT(position.isSpan());
ASSERT(!position.namedGridLine().isNull());
// Negative positions are not allowed per the specification and should have been handled during parsing.
ASSERT(position.spanPosition() > 0);
const NamedGridLinesMap& gridLinesNames = (side == ColumnStartSide || side == ColumnEndSide) ? gridContainerStyle.namedGridColumnLines() : gridContainerStyle.namedGridRowLines();
NamedGridLinesMap::const_iterator it = gridLinesNames.find(position.namedGridLine());
// If there is no named grid line of that name, we resolve the position to 'auto' (which is equivalent to 'span 1' in this case).
// See http://lists.w3.org/Archives/Public/www-style/2013Jun/0394.html.
if (it == gridLinesNames.end())
return GridSpan::create(resolvedOppositePosition, resolvedOppositePosition);
return GridSpan::createWithNamedSpanAgainstOpposite(resolvedOppositePosition, position, side, it->value);
}
示例6: resolveGridPositionFromStyle
GridResolvedPosition GridResolvedPosition::resolveGridPositionFromStyle(const RenderStyle& gridContainerStyle, const GridPosition& position, GridPositionSide side)
{
switch (position.type()) {
case ExplicitPosition: {
ASSERT(position.integerPosition());
if (!position.namedGridLine().isNull())
return resolveNamedGridLinePositionFromStyle(gridContainerStyle, position, side);
// Handle <integer> explicit position.
if (position.isPositive())
return adjustGridPositionForSide(position.integerPosition() - 1, side);
size_t resolvedPosition = abs(position.integerPosition()) - 1;
const size_t endOfTrack = explicitGridSizeForSide(gridContainerStyle, side);
// Per http://lists.w3.org/Archives/Public/www-style/2013Mar/0589.html, we clamp negative value to the first line.
if (endOfTrack < resolvedPosition)
return GridResolvedPosition(0);
return adjustGridPositionForSide(endOfTrack - resolvedPosition, side);
}
case NamedGridAreaPosition:
{
NamedGridAreaMap::const_iterator it = gridContainerStyle.namedGridArea().find(position.namedGridLine());
// Unknown grid area should have been computed to 'auto' by now.
ASSERT_WITH_SECURITY_IMPLICATION(it != gridContainerStyle.namedGridArea().end());
const GridCoordinate& gridAreaCoordinate = it->value;
switch (side) {
case ColumnStartSide:
return gridAreaCoordinate.columns.resolvedInitialPosition;
case ColumnEndSide:
return gridAreaCoordinate.columns.resolvedFinalPosition;
case RowStartSide:
return gridAreaCoordinate.rows.resolvedInitialPosition;
case RowEndSide:
return GridResolvedPosition(gridAreaCoordinate.rows.resolvedFinalPosition);
}
ASSERT_NOT_REACHED();
return GridResolvedPosition(0);
}
case AutoPosition:
case SpanPosition:
// 'auto' and span depend on the opposite position for resolution (e.g. grid-row: auto / 1 or grid-column: span 3 / "myHeader").
ASSERT_NOT_REACHED();
return GridResolvedPosition(0);
}
ASSERT_NOT_REACHED();
return GridResolvedPosition(0);
}
示例7: initialAndFinalPositionsFromStyle
void GridResolvedPosition::initialAndFinalPositionsFromStyle(const ComputedStyle& gridContainerStyle, const LayoutBox& gridItem, GridTrackSizingDirection direction, GridPosition& initialPosition, GridPosition& finalPosition)
{
initialPosition = (direction == ForColumns) ? gridItem.style()->gridColumnStart() : gridItem.style()->gridRowStart();
finalPosition = (direction == ForColumns) ? gridItem.style()->gridColumnEnd() : gridItem.style()->gridRowEnd();
// We must handle the placement error handling code here instead of in the StyleAdjuster because we don't want to
// overwrite the specified values.
if (initialPosition.isSpan() && finalPosition.isSpan())
finalPosition.setAutoPosition();
// Try to early detect the case of non existing named grid lines. This way we could assume later that
// GridResolvedPosition::resolveGrisPositionFromStyle() always return a valid resolved position.
if (initialPosition.isNamedGridArea() && !isValidNamedLineOrArea(initialPosition.namedGridLine(), gridContainerStyle, initialPositionSide(direction)))
initialPosition.setAutoPosition();
if (finalPosition.isNamedGridArea() && !isValidNamedLineOrArea(finalPosition.namedGridLine(), gridContainerStyle, finalPositionSide(direction)))
finalPosition.setAutoPosition();
// If the grid item has an automatic position and a grid span for a named line in a given dimension, instead treat the grid span as one.
if (initialPosition.isAuto() && finalPosition.isSpan() && !finalPosition.namedGridLine().isNull())
finalPosition.setSpanPosition(1, String());
if (finalPosition.isAuto() && initialPosition.isSpan() && !initialPosition.namedGridLine().isNull())
initialPosition.setSpanPosition(1, String());
}
示例8: resolveGridPositionAgainstOppositePosition
GridSpan GridResolvedPosition::resolveGridPositionAgainstOppositePosition(const ComputedStyle& gridContainerStyle, const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, GridPositionSide side)
{
if (position.isAuto()) {
if ((side == ColumnStartSide || side == RowStartSide) && resolvedOppositePosition.toInt())
return GridSpan::definiteGridSpan(resolvedOppositePosition.prev(), resolvedOppositePosition);
return GridSpan::definiteGridSpan(resolvedOppositePosition, resolvedOppositePosition.next());
}
ASSERT(position.isSpan());
ASSERT(position.spanPosition() > 0);
if (!position.namedGridLine().isNull()) {
// span 2 'c' -> we need to find the appropriate grid line before / after our opposite position.
return resolveNamedGridLinePositionAgainstOppositePosition(gridContainerStyle, resolvedOppositePosition, position, side);
}
return GridSpan::definiteGridSpanWithSpanAgainstOpposite(resolvedOppositePosition, position, side);
}
示例9: resolveGridPositionAgainstOppositePosition
static GridSpan resolveGridPositionAgainstOppositePosition(const RenderStyle& gridContainerStyle, int oppositeLine, const GridPosition& position, GridPositionSide side, unsigned autoRepeatTracksCount)
{
if (position.isAuto()) {
if (isStartSide(side))
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine - 1, oppositeLine);
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine, oppositeLine + 1);
}
ASSERT(position.isSpan());
ASSERT(position.spanPosition() > 0);
if (!position.namedGridLine().isNull()) {
// span 2 'c' -> we need to find the appropriate grid line before / after our opposite position.
return resolveNamedGridLinePositionAgainstOppositePosition(gridContainerStyle, oppositeLine, position, side, autoRepeatTracksCount);
}
// 'span 1' is contained inside a single grid track regardless of the direction.
// That's why the CSS span value is one more than the offset we apply.
unsigned positionOffset = position.spanPosition();
if (isStartSide(side))
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine - positionOffset, oppositeLine);
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine, oppositeLine + positionOffset);
}
示例10: adoptPtr
PassOwnPtr<GridSpan> GridResolvedPosition::resolveGridPositionsFromStyle(const RenderStyle& gridContainerStyle, const RenderBox& gridItem, GridTrackSizingDirection direction)
{
GridPosition initialPosition = (direction == ForColumns) ? gridItem.style()->gridColumnStart() : gridItem.style()->gridRowStart();
const GridPositionSide initialPositionSide = (direction == ForColumns) ? ColumnStartSide : RowStartSide;
GridPosition finalPosition = (direction == ForColumns) ? gridItem.style()->gridColumnEnd() : gridItem.style()->gridRowEnd();
const GridPositionSide finalPositionSide = (direction == ForColumns) ? ColumnEndSide : RowEndSide;
// We must handle the placement error handling code here instead of in the StyleAdjuster because we don't want to
// overwrite the specified values.
if (initialPosition.isSpan() && finalPosition.isSpan())
finalPosition.setAutoPosition();
if (initialPosition.isNamedGridArea() && !gridContainerStyle.namedGridArea().contains(initialPosition.namedGridLine()))
initialPosition.setAutoPosition();
if (finalPosition.isNamedGridArea() && !gridContainerStyle.namedGridArea().contains(finalPosition.namedGridLine()))
finalPosition.setAutoPosition();
if (initialPosition.shouldBeResolvedAgainstOppositePosition() && finalPosition.shouldBeResolvedAgainstOppositePosition()) {
if (gridContainerStyle.gridAutoFlow() == AutoFlowNone)
return adoptPtr(new GridSpan(0, 0));
// We can't get our grid positions without running the auto placement algorithm.
return nullptr;
}
if (initialPosition.shouldBeResolvedAgainstOppositePosition()) {
// Infer the position from the final position ('auto / 1' or 'span 2 / 3' case).
GridResolvedPosition finalResolvedPosition = resolveGridPositionFromStyle(gridContainerStyle, finalPosition, finalPositionSide);
return resolveGridPositionAgainstOppositePosition(gridContainerStyle, finalResolvedPosition, initialPosition, initialPositionSide);
}
if (finalPosition.shouldBeResolvedAgainstOppositePosition()) {
// Infer our position from the initial position ('1 / auto' or '3 / span 2' case).
GridResolvedPosition initialResolvedPosition = resolveGridPositionFromStyle(gridContainerStyle, initialPosition, initialPositionSide);
return resolveGridPositionAgainstOppositePosition(gridContainerStyle, initialResolvedPosition, finalPosition, finalPositionSide);
}
GridResolvedPosition resolvedInitialPosition = resolveGridPositionFromStyle(gridContainerStyle, initialPosition, initialPositionSide);
GridResolvedPosition resolvedFinalPosition = resolveGridPositionFromStyle(gridContainerStyle, finalPosition, finalPositionSide);
// If 'grid-after' specifies a line at or before that specified by 'grid-before', it computes to 'span 1'.
if (resolvedFinalPosition < resolvedInitialPosition)
resolvedFinalPosition = resolvedInitialPosition;
return adoptPtr(new GridSpan(resolvedInitialPosition, resolvedFinalPosition));
}