本文整理汇总了C++中GridPosition::isSpan方法的典型用法代码示例。如果您正苦于以下问题:C++ GridPosition::isSpan方法的具体用法?C++ GridPosition::isSpan怎么用?C++ GridPosition::isSpan使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类GridPosition
的用法示例。
在下文中一共展示了GridPosition::isSpan方法的8个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: initialAndFinalPositionsFromStyle
void GridResolvedPosition::initialAndFinalPositionsFromStyle(const RenderStyle& gridContainerStyle, const RenderBox& gridItem, GridTrackSizingDirection direction, GridPosition& initialPosition, GridPosition& finalPosition)
{
initialPosition = (direction == ForColumns) ? gridItem.style()->gridColumnStart() : gridItem.style()->gridRowStart();
finalPosition = (direction == ForColumns) ? gridItem.style()->gridColumnEnd() : gridItem.style()->gridRowEnd();
GridPositionSide initialPositionSide = calculateInitialPositionSide(direction);
GridPositionSide finalPositionSide = calculateFinalPositionSide(direction);
// We must handle the placement error handling code here instead of in the StyleAdjuster because we don't want to
// overwrite the specified values.
if (initialPosition.isSpan() && finalPosition.isSpan())
finalPosition.setAutoPosition();
// Try to early detect the case of non existing named grid lines. This way we could assume later that
// GridResolvedPosition::resolveGrisPositionFromStyle() always return a valid resolved position.
if (initialPosition.isNamedGridArea() && !isValidNamedLineOrArea(initialPosition.namedGridLine(), gridContainerStyle, initialPositionSide))
initialPosition.setAutoPosition();
if (finalPosition.isNamedGridArea() && !isValidNamedLineOrArea(finalPosition.namedGridLine(), gridContainerStyle, finalPositionSide))
finalPosition.setAutoPosition();
// If the grid item has an automatic position and a grid span for a named line in a given dimension, instead treat the grid span as one.
if (initialPosition.isAuto() && finalPosition.isSpan() && !finalPosition.namedGridLine().isNull())
finalPosition.setSpanPosition(1, String());
if (finalPosition.isAuto() && initialPosition.isSpan() && !initialPosition.namedGridLine().isNull())
initialPosition.setSpanPosition(1, String());
}
示例2: adjustGridPositionsFromStyle
static void adjustGridPositionsFromStyle(const RenderStyle& gridContainerStyle, const RenderBox& gridItem, GridTrackSizingDirection direction, GridPosition& initialPosition, GridPosition& finalPosition)
{
bool isForColumns = direction == ForColumns;
initialPosition = isForColumns ? gridItem.style().gridItemColumnStart() : gridItem.style().gridItemRowStart();
finalPosition = isForColumns ? gridItem.style().gridItemColumnEnd() : gridItem.style().gridItemRowEnd();
// We must handle the placement error handling code here instead of in the StyleAdjuster because we don't want to
// overwrite the specified values.
if (initialPosition.isSpan() && finalPosition.isSpan())
finalPosition.setAutoPosition();
if (gridItem.isOutOfFlowPositioned()) {
// Early detect the case of non existing named grid lines for positioned items.
if (initialPosition.isNamedGridArea() && !NamedLineCollection::isValidNamedLineOrArea(initialPosition.namedGridLine(), gridContainerStyle, initialPositionSide(direction)))
initialPosition.setAutoPosition();
if (finalPosition.isNamedGridArea() && !NamedLineCollection::isValidNamedLineOrArea(finalPosition.namedGridLine(), gridContainerStyle, finalPositionSide(direction)))
finalPosition.setAutoPosition();
}
// If the grid item has an automatic position and a grid span for a named line in a given dimension, instead treat the grid span as one.
if (initialPosition.isAuto() && finalPosition.isSpan() && !finalPosition.namedGridLine().isNull())
finalPosition.setSpanPosition(1, String());
if (finalPosition.isAuto() && initialPosition.isSpan() && !initialPosition.namedGridLine().isNull())
initialPosition.setSpanPosition(1, String());
}
示例3: adoptPtr
PassOwnPtr<GridSpan> GridResolvedPosition::resolveGridPositionsFromStyle(const RenderStyle& gridContainerStyle, const RenderBox& gridItem, GridTrackSizingDirection direction)
{
GridPosition initialPosition = (direction == ForColumns) ? gridItem.style()->gridColumnStart() : gridItem.style()->gridRowStart();
const GridPositionSide initialPositionSide = (direction == ForColumns) ? ColumnStartSide : RowStartSide;
GridPosition finalPosition = (direction == ForColumns) ? gridItem.style()->gridColumnEnd() : gridItem.style()->gridRowEnd();
const GridPositionSide finalPositionSide = (direction == ForColumns) ? ColumnEndSide : RowEndSide;
// We must handle the placement error handling code here instead of in the StyleAdjuster because we don't want to
// overwrite the specified values.
if (initialPosition.isSpan() && finalPosition.isSpan())
finalPosition.setAutoPosition();
if (initialPosition.isNamedGridArea() && !gridContainerStyle.namedGridArea().contains(initialPosition.namedGridLine()))
initialPosition.setAutoPosition();
if (finalPosition.isNamedGridArea() && !gridContainerStyle.namedGridArea().contains(finalPosition.namedGridLine()))
finalPosition.setAutoPosition();
if (initialPosition.shouldBeResolvedAgainstOppositePosition() && finalPosition.shouldBeResolvedAgainstOppositePosition()) {
if (gridContainerStyle.gridAutoFlow() == AutoFlowNone)
return adoptPtr(new GridSpan(0, 0));
// We can't get our grid positions without running the auto placement algorithm.
return nullptr;
}
if (initialPosition.shouldBeResolvedAgainstOppositePosition()) {
// Infer the position from the final position ('auto / 1' or 'span 2 / 3' case).
GridResolvedPosition finalResolvedPosition = resolveGridPositionFromStyle(gridContainerStyle, finalPosition, finalPositionSide);
return resolveGridPositionAgainstOppositePosition(gridContainerStyle, finalResolvedPosition, initialPosition, initialPositionSide);
}
if (finalPosition.shouldBeResolvedAgainstOppositePosition()) {
// Infer our position from the initial position ('1 / auto' or '3 / span 2' case).
GridResolvedPosition initialResolvedPosition = resolveGridPositionFromStyle(gridContainerStyle, initialPosition, initialPositionSide);
return resolveGridPositionAgainstOppositePosition(gridContainerStyle, initialResolvedPosition, finalPosition, finalPositionSide);
}
GridResolvedPosition resolvedInitialPosition = resolveGridPositionFromStyle(gridContainerStyle, initialPosition, initialPositionSide);
GridResolvedPosition resolvedFinalPosition = resolveGridPositionFromStyle(gridContainerStyle, finalPosition, finalPositionSide);
// If 'grid-after' specifies a line at or before that specified by 'grid-before', it computes to 'span 1'.
if (resolvedFinalPosition < resolvedInitialPosition)
resolvedFinalPosition = resolvedInitialPosition;
return adoptPtr(new GridSpan(resolvedInitialPosition, resolvedFinalPosition));
}
示例4: resolveNamedGridLinePositionAgainstOppositePosition
static GridSpan resolveNamedGridLinePositionAgainstOppositePosition(const RenderStyle& gridContainerStyle, int oppositeLine, const GridPosition& position, GridPositionSide side, unsigned autoRepeatTracksCount)
{
ASSERT(position.isSpan());
ASSERT(!position.namedGridLine().isNull());
// Negative positions are not allowed per the specification and should have been handled during parsing.
ASSERT(position.spanPosition() > 0);
unsigned lastLine = explicitGridSizeForSide(gridContainerStyle, side, autoRepeatTracksCount);
NamedLineCollection linesCollection(gridContainerStyle, position.namedGridLine(), directionFromSide(side), lastLine, autoRepeatTracksCount);
return definiteGridSpanWithNamedLineSpanAgainstOpposite(oppositeLine, position, side, lastLine, linesCollection);
}
示例5: create
PassOwnPtr<GridSpan> GridResolvedPosition::resolveGridPositionAgainstOppositePosition(const RenderStyle& gridContainerStyle, const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, GridPositionSide side)
{
if (position.isAuto())
return GridSpan::create(resolvedOppositePosition, resolvedOppositePosition);
ASSERT(position.isSpan());
ASSERT(position.spanPosition() > 0);
if (!position.namedGridLine().isNull()) {
// span 2 'c' -> we need to find the appropriate grid line before / after our opposite position.
return resolveNamedGridLinePositionAgainstOppositePosition(gridContainerStyle, resolvedOppositePosition, position, side);
}
return GridSpan::createWithSpanAgainstOpposite(resolvedOppositePosition, position, side);
}
示例6: spanSizeForAutoPlacedItem
unsigned GridPositionsResolver::spanSizeForAutoPlacedItem(const RenderStyle& gridContainerStyle, const RenderBox& gridItem, GridTrackSizingDirection direction)
{
GridPosition initialPosition, finalPosition;
adjustGridPositionsFromStyle(gridContainerStyle, gridItem, direction, initialPosition, finalPosition);
// This method will only be used when both positions need to be resolved against the opposite one.
ASSERT(initialPosition.shouldBeResolvedAgainstOppositePosition() && finalPosition.shouldBeResolvedAgainstOppositePosition());
if (initialPosition.isAuto() && finalPosition.isAuto())
return 1;
GridPosition position = initialPosition.isSpan() ? initialPosition : finalPosition;
ASSERT(position.isSpan());
ASSERT(position.spanPosition());
return position.spanPosition();
}
示例7: resolveGridPositionAgainstOppositePosition
GridSpan GridResolvedPosition::resolveGridPositionAgainstOppositePosition(const ComputedStyle& gridContainerStyle, const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, GridPositionSide side)
{
if (position.isAuto()) {
if ((side == ColumnStartSide || side == RowStartSide) && resolvedOppositePosition.toInt())
return GridSpan::definiteGridSpan(resolvedOppositePosition.prev(), resolvedOppositePosition);
return GridSpan::definiteGridSpan(resolvedOppositePosition, resolvedOppositePosition.next());
}
ASSERT(position.isSpan());
ASSERT(position.spanPosition() > 0);
if (!position.namedGridLine().isNull()) {
// span 2 'c' -> we need to find the appropriate grid line before / after our opposite position.
return resolveNamedGridLinePositionAgainstOppositePosition(gridContainerStyle, resolvedOppositePosition, position, side);
}
return GridSpan::definiteGridSpanWithSpanAgainstOpposite(resolvedOppositePosition, position, side);
}
示例8: resolveGridPositionAgainstOppositePosition
static GridSpan resolveGridPositionAgainstOppositePosition(const RenderStyle& gridContainerStyle, int oppositeLine, const GridPosition& position, GridPositionSide side, unsigned autoRepeatTracksCount)
{
if (position.isAuto()) {
if (isStartSide(side))
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine - 1, oppositeLine);
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine, oppositeLine + 1);
}
ASSERT(position.isSpan());
ASSERT(position.spanPosition() > 0);
if (!position.namedGridLine().isNull()) {
// span 2 'c' -> we need to find the appropriate grid line before / after our opposite position.
return resolveNamedGridLinePositionAgainstOppositePosition(gridContainerStyle, oppositeLine, position, side, autoRepeatTracksCount);
}
// 'span 1' is contained inside a single grid track regardless of the direction.
// That's why the CSS span value is one more than the offset we apply.
unsigned positionOffset = position.spanPosition();
if (isStartSide(side))
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine - positionOffset, oppositeLine);
return GridSpan::untranslatedDefiniteGridSpan(oppositeLine, oppositeLine + positionOffset);
}