本文整理汇总了C++中FixedArray::data方法的典型用法代码示例。如果您正苦于以下问题：C++ FixedArray::data方法的具体用法？C++ FixedArray::data怎么用？C++ FixedArray::data使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类FixedArray的用法示例。
在下文中一共展示了FixedArray::data方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: dump
void CodeBlockHash::dump(PrintStream& out) const
{
FixedArray<char, 7> buffer = integerToSixCharacterHashString(m_hash);
#if !ASSERT_DISABLED
CodeBlockHash recompute(buffer.data());
ASSERT(recompute == *this);
#endif // !ASSERT_DISABLED
out.print(buffer.data());
}示例2: qsort
OpcodeStats::~OpcodeStats()
{
long long totalInstructions = 0;
for (int i = 0; i < numOpcodeIDs; ++i)
totalInstructions += opcodeCounts[i];
long long totalInstructionPairs = 0;
for (int i = 0; i < numOpcodeIDs; ++i)
for (int j = 0; j < numOpcodeIDs; ++j)
totalInstructionPairs += opcodePairCounts[i][j];
FixedArray<int, numOpcodeIDs> sortedIndices;
for (int i = 0; i < numOpcodeIDs; ++i)
sortedIndices[i] = i;
qsort(sortedIndices.data(), numOpcodeIDs, sizeof(int), compareOpcodeIndices);
pair<int, int> sortedPairIndices[numOpcodeIDs * numOpcodeIDs];
pair<int, int>* currentPairIndex = sortedPairIndices;
for (int i = 0; i < numOpcodeIDs; ++i)
for (int j = 0; j < numOpcodeIDs; ++j)
*(currentPairIndex++) = make_pair(i, j);
qsort(sortedPairIndices, numOpcodeIDs * numOpcodeIDs, sizeof(pair<int, int>), compareOpcodePairIndices);
printf("\nExecuted opcode statistics\n");
printf("Total instructions executed: %lld\n\n", totalInstructions);
printf("All opcodes by frequency:\n\n");
for (int i = 0; i < numOpcodeIDs; ++i) {
int index = sortedIndices[i];
printf("%s:%s %lld - %.2f%%\n", opcodeNames[index], padOpcodeName((OpcodeID)index, 28), opcodeCounts[index], ((double) opcodeCounts[index]) / ((double) totalInstructions) * 100.0);
}
printf("\n");
printf("2-opcode sequences by frequency: %lld\n\n", totalInstructions);
for (int i = 0; i < numOpcodeIDs * numOpcodeIDs; ++i) {
pair<int, int> indexPair = sortedPairIndices[i];
long long count = opcodePairCounts[indexPair.first][indexPair.second];
if (!count)
break;
printf("%s%s %s:%s %lld %.2f%%\n", opcodeNames[indexPair.first], padOpcodeName((OpcodeID)indexPair.first, 28), opcodeNames[indexPair.second], padOpcodeName((OpcodeID)indexPair.second, 28), count, ((double) count) / ((double) totalInstructionPairs) * 100.0);
}
printf("\n");
printf("Most common opcodes and sequences:\n");
for (int i = 0; i < numOpcodeIDs; ++i) {
int index = sortedIndices[i];
long long opcodeCount = opcodeCounts[index];
double opcodeProportion = ((double) opcodeCount) / ((double) totalInstructions);
if (opcodeProportion < 0.0001)
break;
printf("\n%s:%s %lld - %.2f%%\n", opcodeNames[index], padOpcodeName((OpcodeID)index, 28), opcodeCount, opcodeProportion * 100.0);
for (int j = 0; j < numOpcodeIDs * numOpcodeIDs; ++j) {
pair<int, int> indexPair = sortedPairIndices[j];
long long pairCount = opcodePairCounts[indexPair.first][indexPair.second];
double pairProportion = ((double) pairCount) / ((double) totalInstructionPairs);
if (!pairCount || pairProportion < 0.0001 || pairProportion < opcodeProportion / 100)
break;
if (indexPair.first != index && indexPair.second != index)
continue;
printf(" %s%s %s:%s %lld - %.2f%%\n", opcodeNames[indexPair.first], padOpcodeName((OpcodeID)indexPair.first, 28), opcodeNames[indexPair.second], padOpcodeName((OpcodeID)indexPair.second, 28), pairCount, pairProportion * 100.0);
}
}
printf("\n");
}