本文整理汇总了C++中Datum::GetScope方法的典型用法代码示例。如果您正苦于以下问题：C++ Datum::GetScope方法的具体用法？C++ Datum::GetScope怎么用？C++ Datum::GetScope使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Datum的用法示例。
在下文中一共展示了Datum::GetScope方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: exception
Scope& Scope::AppendScope(const std::string& key)
{
Datum* datum = Find(key);
//TODO: Push Back when removing from Vector
//Found key, check if type is table
if (datum)
{
if (datum->IsExternal() || (datum->GetType() != Datum::DatumType::Table))
{
throw std::exception("This Datum is not of the right type");
}
Scope* newScope = new Scope();
newScope->mParent = this;
datum->Set(newScope, datum->Size());
return *datum->GetScope(datum->Size() - 1);
}
else
{
//key not found
Datum& d = Append(key, Datum::DatumType::Table);
Scope* newScope = new Scope();
newScope->mParent = this;
d.Set(newScope, 0);
return *d.GetScope(0);
}
}示例2: Adopt
void Scope::Adopt(Scope& childToAdopt, const std::string& key, const std::uint32_t index)
{
if (childToAdopt.GetParent())
childToAdopt.Orphan();
Datum * foundDatum = Find(key);
if (foundDatum)
{
if ((foundDatum->GetType() != Datum::DatumType::Table) || foundDatum->IsExternal())
throw std::exception("You are trying to adopt into a invalid scope");
if ((foundDatum->GetType() == Datum::DatumType::Table))
{
if (index >= foundDatum->Size())
{
foundDatum->Set(&childToAdopt, index);
foundDatum->GetScope(index)->mParent = this;
}
else
{
Scope* temp = foundDatum->GetScope(index);
foundDatum->Set(&childToAdopt, index);
foundDatum->GetScope(index)->mParent = this;
for (std::uint32_t i = index + 1; i < foundDatum->Size(); ++i)
{
Scope* temp2 = foundDatum->GetScope(i);
foundDatum->Set(temp, i);
temp = temp2;
}
foundDatum->Set(temp, foundDatum->Size());
}
}
}
else
{
Datum& d = Append(key, Datum::DatumType::Table);
d.Set(&childToAdopt);
d.GetScope()->mParent = this;
}
}