本文整理汇总了C++中BigNumber::add方法的典型用法代码示例。如果您正苦于以下问题：C++ BigNumber::add方法的具体用法？C++ BigNumber::add怎么用？C++ BigNumber::add使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类BigNumber的用法示例。
在下文中一共展示了BigNumber::add方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: evalNode
void evalNode(BigNumber &n, int i, DdValues<BigNumber, ARITY> const &values)
{
assert(size_t(i) <= pools.size());
if (BDD) {
int w = tmp1.store(0);
for (int b = 0; b < ARITY; ++b) {
tmp2.store(values.get(b));
tmp2.shiftLeft(i - values.getLevel(b) - 1);
w = tmp1.add(tmp2);
}
n.setArray(pools[i].template allocate<uint64_t>(w));
n.store(tmp1);
} else {
int w;
if (ARITY <= 0) {
w = tmp1.store(0);
} else {
w = tmp1.store(values.get(0));
for (int b = 1; b < ARITY; ++b) {
w = tmp1.add(values.get(b));
}
}
n.setArray(pools[i].template allocate<uint64_t>(w));
n.store(tmp1);
}
}示例2: evalNode
void evalNode(BigNumber& n,
int i,
DdValues<BigNumber,ARITY> const& values) {
assert(0 <= i && size_t(i) <= pools.size());
if (BDD) {
size_t w = tmp1.store(0);
for (int b = 0; b < ARITY; ++b) {
tmp2.store(values.get(b));
int k = i - values.getLevel(b) - 1;
if (ARITY == 2) {
tmp2.shiftLeft(k);
}
else {
while (--k >= 0) {
tmp3.store(tmp2);
for (int b = 1; b < ARITY; ++b) {
tmp2.add(tmp3);
}
}
}
w = tmp1.add(tmp2);
}
n.setArray(pools[i].allocate<uint64_t>(w));
n.store(tmp1);
}
else {
size_t w;
if (ARITY <= 0) {
w = tmp1.store(0);
}
else {
w = tmp1.store(values.get(0));
for (int b = 1; b < ARITY; ++b) {
w = tmp1.add(values.get(b));
}
}
n.setArray(pools[i].allocate<uint64_t>(w));
n.store(tmp1);
}
}示例3: main
int main() {
assert(BigNumber(6, 9).toString() == "6.9");
assert(BigNumber(3).toString() == "3");
assert(BigNumber(-5).toString() == "-5");
vector<string> v = {"10", "10.3", "-10.555", "69.34433434", "0", "2"};
for (int i = 0; i < v.size(); i++)
assert(BigNumber(v[i]).toString() == v[i]);
BigNumber nineteen = BigNumber(19);
nineteen.plus_one();
assert(nineteen.toString() == "20");
BigNumber x = BigNumber(8);
x.plus_one();
assert(x.toString() == "9");
x.plus_one();
assert(x.toString() == "10");
BigNumber y = BigNumber("10.6");
y.plus_one();
assert(y.toString() == "11.6");
BigNumber ten = BigNumber("5.1");
ten.add(BigNumber("3.2"));
assert(ten.toString() == "8.3");
ten.add(BigNumber("1.12"));
assert(ten.toString() == "9.42");
ten.add(BigNumber("0.1"));
assert(ten.toString() == "9.52");
ten.add(BigNumber("0.000001"));
assert(ten.toString() == "9.520001");
return 0;
}示例4: solve
BigNumber solve(int l, int b, int p) {
for (int i = 0; i <= l; ++i)
for (int j = 0; j <= p; ++j)
dp[i][j] = BigNumberZ;
dp[1][0] = BigNumber(b);
for (int i = 2; i <= l; ++i) {
for (int k = 0; k <= p; ++k) {
dp[i][0].add(dp[i - 1][k] * b);
if (k != 0)
dp[i][k] = dp[i - 1][k - 1];
}
}
BigNumber rez;
for (int k = 0; k <= p; ++k)
rez.add(dp[l][k]);
return rez;
}示例5: getValue
std::string getValue(BigNumber const& n) {
if (BDD) {
tmp2.store(n);
int k = numVars - topLevel;
if (ARITY == 2) {
tmp2.shiftLeft(k);
}
else {
while (--k >= 0) {
tmp3.store(tmp2);
for (int b = 1; b < ARITY; ++b) {
tmp2.add(tmp3);
}
}
}
return tmp2;
}
else {
return n;
}
}