本文整理汇总了C++中ArtifactSet::empty方法的典型用法代码示例。如果您正苦于以下问题：C++ ArtifactSet::empty方法的具体用法？C++ ArtifactSet::empty怎么用？C++ ArtifactSet::empty使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ArtifactSet的用法示例。
在下文中一共展示了ArtifactSet::empty方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: apply
void RuleNode::apply(const Logger &logger,
const std::unordered_map<QString, const ResolvedProduct *> &productsByName,
const std::unordered_map<QString, const ResolvedProject *> &projectsByName,
ApplicationResult *result)
{
ArtifactSet allCompatibleInputs = currentInputArtifacts();
const ArtifactSet explicitlyDependsOn
= RulesApplicator::collectExplicitlyDependsOn(m_rule.get(), product.get());
const ArtifactSet auxiliaryInputs
= RulesApplicator::collectAuxiliaryInputs(m_rule.get(), product.get());
const ArtifactSet addedInputs = allCompatibleInputs - m_oldInputArtifacts;
const ArtifactSet removedInputs = m_oldInputArtifacts - allCompatibleInputs;
const ArtifactSet changedInputs = changedInputArtifacts(allCompatibleInputs,
explicitlyDependsOn,
auxiliaryInputs);
bool upToDate = changedInputs.empty() && addedInputs.empty() && removedInputs.empty();
qCDebug(lcBuildGraph).noquote().nospace()
<< "consider " << (m_rule->isDynamic() ? "dynamic " : "")
<< (m_rule->multiplex ? "multiplex " : "")
<< "rule node " << m_rule->toString()
<< "\n\tchanged: " << changedInputs.toString()
<< "\n\tcompatible: " << allCompatibleInputs.toString()
<< "\n\tadded: " << addedInputs.toString()
<< "\n\tremoved: " << removedInputs.toString();
ArtifactSet inputs = changedInputs;
if (m_rule->multiplex)
inputs = allCompatibleInputs;
else
inputs += addedInputs;
for (Artifact * const input : allCompatibleInputs) {
for (const Artifact * const output : input->parentArtifacts()) {
if (output->transformer->rule != m_rule)
continue;
if (prepareScriptNeedsRerun(output->transformer.get(),
output->transformer->product().get(),
productsByName, projectsByName)) {
upToDate = false;
inputs += input;
}
break;
}
if (m_rule->multiplex)
break;
}
// Handle rules without inputs: We want to run such a rule if and only if it has not run yet
// or its transformer is not up to date regarding the prepare script.
if (upToDate && (!m_rule->declaresInputs() || !m_rule->requiresInputs) && inputs.empty()) {
bool hasOutputs = false;
for (const Artifact * const output : filterByType<Artifact>(parents)) {
if (output->transformer->rule != m_rule)
continue;
hasOutputs = true;
if (prepareScriptNeedsRerun(output->transformer.get(),
output->transformer->product().get(),
productsByName, projectsByName)) {
upToDate = false;
break;
}
if (m_rule->multiplex)
break;
}
if (!hasOutputs)
upToDate = false;
}
if (upToDate) {
qCDebug(lcExec) << "rule is up to date. Skipping.";
return;
}
const bool mustApplyRule = !inputs.empty() || !m_rule->declaresInputs()
|| !m_rule->requiresInputs;
// For a non-multiplex rule, the removal of an input always implies that the
// corresponding outputs disappear.
// For a multiplex rule, the outputs disappear only if *all* inputs are gone *and*
// the rule requires inputs. This is exactly the opposite condition of whether to
// re-apply the rule.
const bool removedInputForcesOutputRemoval = !m_rule->multiplex || !mustApplyRule;
ArtifactSet outputArtifactsToRemove;
std::vector<std::pair<Artifact *, Artifact *>> connectionsToBreak;
for (Artifact * const artifact : removedInputs) {
if (!artifact) // dummy artifact
continue;
for (Artifact *parent : filterByType<Artifact>(artifact->parents)) {
if (parent->transformer->rule != m_rule) {
// parent was not created by our rule.
continue;
}
// parent must always have a transformer, because it's generated.
QBS_CHECK(parent->transformer);
// artifact is a former input of m_rule and parent was created by m_rule
// the inputs of the transformer must contain artifact
QBS_CHECK(parent->transformer->inputs.contains(artifact));
//.........这里部分代码省略.........