R dplyr cumall 任何、全部和平均值的累積版本

cumall(x)

cumany(x)

cummean(x)

# `cummean()` returns a numeric/integer vector of the same length
# as the input vector.
x <- c(1, 3, 5, 2, 2)
cummean(x)
#> [1] 1.00 2.00 3.00 2.75 2.60
cumsum(x) / seq_along(x)
#> [1] 1.00 2.00 3.00 2.75 2.60

# `cumall()` and `cumany()` return logicals
cumall(x < 5)
#> [1]  TRUE  TRUE FALSE FALSE FALSE
cumany(x == 3)
#> [1] FALSE  TRUE  TRUE  TRUE  TRUE

# `cumall()` vs. `cumany()`
df <- data.frame(
  date = as.Date("2020-01-01") + 0:6,
  balance = c(100, 50, 25, -25, -50, 30, 120)
)
# all rows after first overdraft
df %>% filter(cumany(balance < 0))
#>         date balance
#> 1 2020-01-04     -25
#> 2 2020-01-05     -50
#> 3 2020-01-06      30
#> 4 2020-01-07     120
# all rows until first overdraft
df %>% filter(cumall(!(balance < 0)))
#>         date balance
#> 1 2020-01-01     100
#> 2 2020-01-02      50
#> 3 2020-01-03      25