Python zip()用法及代碼示例

languages = ['Java', 'Python', 'JavaScript']
versions = [14, 3, 6]

result = zip(languages, versions)
print(list(result))

# Output: [('Java', 14), ('Python', 3), ('JavaScript', 6)]

用法:

用法:

zip(*iterables)

參數：

返回：

zip() 函數返回基於可迭代對象的元組迭代器。

• 如果我們不傳遞任何參數，zip() 返回一個空的迭代器
• 如果傳遞了一個可迭代對象，zip() 返回一個元組迭代器，每個元組隻有一個元素。
• 如果傳遞了多個迭代，zip()返回一個元組的迭代器，每個元組都有來自所有可迭代對象的元素。
  
  假設，兩個迭代被傳遞給zip();一個包含三個元素的迭代，另一個包含五個元素。然後，返回的迭代器將包含三個元組。這是因為迭代器在最短的迭代用完時停止。

示例 1：Python zip()

number_list = [1, 2, 3]
str_list = ['one', 'two', 'three']

# No iterables are passed
result = zip()

# Converting iterator to list
result_list = list(result)
print(result_list)

# Two iterables are passed
result = zip(number_list, str_list)

# Converting iterator to set
result_set = set(result)
print(result_set)

輸出

[]
{(2, 'two'), (3, 'three'), (1, 'one')}

示例 2：不同數量的可迭代元素

numbersList = [1, 2, 3]
str_list = ['one', 'two']
numbers_tuple = ('ONE', 'TWO', 'THREE', 'FOUR')

# Notice, the size of numbersList and numbers_tuple is different
result = zip(numbersList, numbers_tuple)

# Converting to set
result_set = set(result)
print(result_set)

result = zip(numbersList, str_list, numbers_tuple)

# Converting to set
result_set = set(result)
print(result_set)

輸出

{(2, 'TWO'), (3, 'THREE'), (1, 'ONE')}
{(2, 'two', 'TWO'), (1, 'one', 'ONE')}

*運算符可以與zip()解壓縮列表。

zip(*zippedList)

示例 3：使用 zip() 解壓縮值

coordinate = ['x', 'y', 'z']
value = [3, 4, 5]

result = zip(coordinate, value)
result_list = list(result)
print(result_list)

c, v =  zip(*result_list)
print('c =', c)
print('v =', v)

輸出

[('x', 3), ('y', 4), ('z', 5)]
c = ('x', 'y', 'z')
v = (3, 4, 5)