Java中的AbstractSequentialList iterator()方法用於在列表上獲取Iterator或List Iterator。它返回此列表中元素的迭代器(按適當順序)。此方法重寫類AbstractList <E>中的iterator()
用法:
public Iterator<E> iterator()
返回值:此方法返回此列表中元素的迭代器(按適當順序)。
下麵的代碼說明了iterator()方法:
程序1:
// Java program to demonstrate
// iterator() method
import java.util.*;
public class GfG {
public static void main(String[] args)
{
// Creating an instance of the AbstractSequentialList
AbstractSequentialList<Integer> absl = new LinkedList<>();
// adding elements to absl
absl.add(5);
absl.add(6);
absl.add(7);
absl.add(2, 8);
absl.add(2, 7);
absl.add(1, 9);
absl.add(4, 10);
// Getting Iterator
Iterator<Integer> Itr = absl.iterator();
// Traversing elements with help of iterator
while (Itr.hasNext()) {
System.out.print(Itr.next() + " ");
}
}
}
輸出:
5 9 6 7 10 8 7
程序2:
// Java program to demonstrate
// iterator() method
import java.util.*;
public class GfG {
public static void main(String[] args)
{
// Creating an instance of the AbstractSequentialList
AbstractSequentialList<String> absl = new LinkedList<>();
// adding elements to absl
absl.add("Geeks");
absl.add("ForGeeks");
absl.add("A");
absl.add("Portal");
absl.add(3, "Computer Science");
absl.add(5, "For Geeks");
// Getting Iterator
Iterator<String> Itr = absl.iterator();
// Traversing elements with help of iterator
while (Itr.hasNext()) {
System.out.println(Itr.next());
}
}
}
輸出:
Geeks ForGeeks A Computer Science Portal For Geeks
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