Java AbstractSequentialList retainAll()用法及代碼示例

java.util.AbstractSequentialList類的retainAll()方法用於從此列表保留指定集合中包含的所有元素。

用法:

public boolean retainAll(Collection c)

參數：此方法將集合c作為包含要從此列表保留的元素的參數。

返回值：如果此列表由於調用而更改，則此方法返回true。

異常：如果此列表包含null元素並且指定的集合不允許null元素(可選)，或者指定的collection為null，則此方法引發NullPointerException。

以下示例說明了retainAll()方法。

範例1：

// Java program to demonstrate 
// retainAll() method for Integer value 
  
import java.util.*; 
  
public class GFG1 { 
    public static void main(String[] argv) throws Exception 
    { 
  
        try { 
  
            // Creating object of AbstractSequentialList<Integer> 
            AbstractSequentialList<Integer> 
                arrlist1 = new LinkedList<Integer>(); 
  
            // Populating arrlist1 
            arrlist1.add(1); 
            arrlist1.add(2); 
            arrlist1.add(3); 
            arrlist1.add(4); 
            arrlist1.add(5); 
  
            // print arrlist1 
            System.out.println("AbstractSequentialList before "
                               + "retainAll() operation:"
                               + arrlist1); 
  
            // Creating another object of  AbstractSequentialList<Integer> 
            AbstractSequentialList<Integer> 
                arrlist2 = new LinkedList<Integer>(); 
            arrlist2.add(1); 
            arrlist2.add(2); 
            arrlist2.add(3); 
  
            // print arrlist2 
            System.out.println("Collection Elements"
                               + " to be retaind:"
                               + arrlist2); 
  
            // Removing elements from arrlist 
            // specified in arrlist2 
            // using retainAll() method 
            arrlist1.retainAll(arrlist2); 
  
            // print arrlist1 
            System.out.println("AbstractSequentialList after "
                               + "retainAll() operation:"
                               + arrlist1); 
        } 
  
        catch (NullPointerException e) { 
            System.out.println("Exception thrown:" + e); 
        } 
    } 
}

輸出：

AbstractSequentialList before retainAll() operation:[1, 2, 3, 4, 5]
Collection Elements to be retaind:[1, 2, 3]
AbstractSequentialList after retainAll() operation:[1, 2, 3]

範例2：對於NullPointerException

// Java program to demonstrate 
// retainAll() method for Integer value 
  
import java.util.*; 
  
public class GFG1 { 
    public static void main(String[] argv) throws Exception 
    { 
  
        try { 
  
            // Creating object of AbstractSequentialList<Integer> 
            AbstractSequentialList<Integer> 
                arrlist1 = new LinkedList<Integer>(); 
  
            // Populating arrlist1 
            arrlist1.add(1); 
            arrlist1.add(2); 
            arrlist1.add(3); 
            arrlist1.add(4); 
            arrlist1.add(5); 
  
            // print arrlist1 
            System.out.println("AbstractSequentialList before "
                               + "retainAll() operation:"
                               + arrlist1); 
  
            // Creating another object of  AbstractSequentialList<Integer> 
            AbstractSequentialList<Integer> 
                arrlist2 = null; 
  
            // print arrlist2 
            System.out.println("Collection Elements"
                               + " to be retaind:"
                               + arrlist2); 
  
            System.out.println("\nTrying to pass "
                               + "null as a specified element\n"); 
  
            // Removing elements from arrlist 
            // specified in arrlist2 
            // using retainAll() method 
            arrlist1.retainAll(arrlist2); 
  
            // print arrlist1 
            System.out.println("AbstractSequentialList after "
                               + "retainAll() operation:"
                               + arrlist1); 
        } 
  
        catch (NullPointerException e) { 
            System.out.println("Exception thrown:" + e); 
        } 
    } 
}

輸出：

AbstractSequentialList before retainAll() operation:[1, 2, 3, 4, 5]
Collection Elements to be retaind:null

Trying to pass null as a specified element

Exception thrown:java.lang.NullPointerException

相關用法

注：本文由純淨天空篩選整理自Code_r大神的英文原創作品 AbstractSequentialList retainAll() method in Java with Example。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。