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d3.js node.sum()用法及代碼示例

d3.js中的node.sum()函數用於評估特定節點的指定值函數。此函數的node.value屬性包含指定函數返回的值。

用法:

node.sum(value);

參數:該函數接受如上所述和以下描述的單個參數:

  • value:這需要為每個節點評估一個函數。

返回值:此函數返回一個對象。

下麵給出的是上麵給出的函數的一些例子。



範例1:

HTML

<!DOCTYPE html>  
<html lang = "en">  
<head>  
    <meta charset = "UTF-8" />  
    <meta name = "viewport"
          path1tent = "width=device-width,  
                       initial-scale = 1.0"/>  
    <script src = 
"https://d3js.org/d3.v4.min.js"> 
    </script> 
</head>  
  
<body>  
    <script>  
       // Constructing a tree 
        var tree={ 
            name:"rootNode", // Root node 
            children:[ 
                { 
                    name:"child1", // Child of root node 
                    value:2 
                }, 
                { 
                    name:"child2", // Child of root node 
                    value:3, 
                    children:[ 
                        { 
                            name:"grandchild1", // Child of child2 
                            value:1, 
                            children:[ 
                                {name:"grand_granchild1_1",value:4},                               
                                // Child of grandchild1 
                                {name:"grand_granchild1_2",value:5}                      
                               // Child of grandchild1 
                            ] 
                        }, 
                        { 
                            name:"grandchild2", 
                            children:[ 
                                {name:"grand_granchild2_1"},   
                                // Child of grandchild2 
                                {name:"grand_granchild2_2"}   
                                // Child of grandchild2 
                            ] 
                        }, 
                    ] 
                } 
            ] 
        }; 
  
        var obj = d3.hierarchy(tree); 
        var grandchild2=obj.children[1].children[1]; 
          
        var sum=obj.sum(d=>d.value); 
        console.log(sum); 
        console.log("The sum of value is:",sum.value); 
    </script>  
</body>  
</html>

輸出:

範例2:

HTML

<!DOCTYPE html>  
<html lang = "en">  
<head>  
    <meta charset = "UTF-8" />  
    <meta name = "viewport"
          path1tent = "width=device-width,  
                       initial-scale = 1.0"/>  
    <script src = 
"https://d3js.org/d3.v4.min.js"> 
    </script> 
</head>  
<body>  
    <script>  
    // Constructing a tree 
        var tree={ 
            name:"rootNode", // Root node 
            children:[ 
                {value:1}, 
                {value:2}, 
                {value:3}, 
                {value:4}, 
                {value:5}, 
                {value:6}, 
            ] 
        }; 
  
        var obj = d3.hierarchy(tree); 
          
        var sum=obj.sum(d=>d.value*12); 
        // 1 + 2 + 3 + 4 + 5 + 6 = 21*12=252 
        console.log(sum); 
        console.log("The value is:",sum.value); 
    </script>  
</body>  
</html>

輸出:




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注:本文由純淨天空篩選整理自tarun007大神的英文原創作品 D3.js node.sum() Function。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。