本文整理匯總了Python中pyomo.core.ConcreteModel.z方法的典型用法代碼示例。如果您正苦於以下問題：Python ConcreteModel.z方法的具體用法？Python ConcreteModel.z怎麽用？Python ConcreteModel.z使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類pyomo.core.ConcreteModel的用法示例。
在下文中一共展示了ConcreteModel.z方法的6個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: test_indexedvar_noindextemplate
# 需要導入模塊: from pyomo.core import ConcreteModel [as 別名]
# 或者: from pyomo.core.ConcreteModel import z [as 別名]
def test_indexedvar_noindextemplate(self):
st_model = CreateConcreteTwoStageScenarioTreeModel(1)
st_model.StageVariables['Stage1'].add("x")
st_model.StageDerivedVariables['Stage1'].add("y")
st_model.NodeVariables['RootNode'].add("z")
st_model.NodeDerivedVariables['RootNode'].add("q")
st_model.StageCost['Stage1'] = "FirstStageCost"
st_model.StageCost['Stage2'] = "SecondStageCost"
scenario_tree = ScenarioTree(scenariotreeinstance=st_model)
self.assertEqual(len(scenario_tree.stages), 2)
self.assertEqual(len(scenario_tree.nodes), 2)
self.assertEqual(len(scenario_tree.scenarios), 1)
model = ConcreteModel()
model.s = Set(initialize=[1,2,3])
model.x = Var(model.s)
model.y = Var(model.s)
model.z = Var(model.s)
model.q = Var(model.s)
model.FirstStageCost = Expression(expr=0.0)
model.SecondStageCost = Expression(expr=0.0)
model.obj = Objective(expr=0.0)
scenario_tree.linkInInstances({'Scenario1': model})
root = scenario_tree.findRootNode()
self.assertEqual(len(root._variable_ids), 12)
self.assertEqual(len(root._standard_variable_ids), 6)
self.assertEqual(len(root._derived_variable_ids), 6)
for name in ("x", "y", "z", "q"):
for index in model.s:
self.assertEqual(
(name,index) in root._name_index_to_id, True)示例2: test_singletonvar_wildcardtemplate
# 需要導入模塊: from pyomo.core import ConcreteModel [as 別名]
# 或者: from pyomo.core.ConcreteModel import z [as 別名]
def test_singletonvar_wildcardtemplate(self):
st_model = CreateConcreteTwoStageScenarioTreeModel(1)
st_model.StageVariables['Stage1'].add("x[*]")
st_model.StageDerivedVariables['Stage1'].add("y[*]")
st_model.NodeVariables['RootNode'].add("z[*]")
st_model.NodeDerivedVariables['RootNode'].add("q[*]")
st_model.StageCost['Stage1'] = "FirstStageCost"
st_model.StageCost['Stage2'] = "SecondStageCost"
scenario_tree = ScenarioTree(scenariotreeinstance=st_model)
self.assertEqual(len(scenario_tree.stages), 2)
self.assertEqual(len(scenario_tree.nodes), 2)
self.assertEqual(len(scenario_tree.scenarios), 1)
model = ConcreteModel()
model.x = Var()
model.y = Var()
model.z = Var()
model.q = Var()
model.FirstStageCost = Expression(expr=0.0)
model.SecondStageCost = Expression(expr=0.0)
model.obj = Objective(expr=0.0)
scenario_tree.linkInInstances({'Scenario1': model})
root = scenario_tree.findRootNode()
self.assertEqual(len(root._variable_ids), 4)
self.assertEqual(len(root._standard_variable_ids), 2)
self.assertEqual(len(root._derived_variable_ids), 2)
for name in ("x", "y", "z", "q"):
for index in [None]:
self.assertEqual(
(name,index) in root._name_index_to_id, True)示例3: test_lmtd
# 需要導入模塊: from pyomo.core import ConcreteModel [as 別名]
# 或者: from pyomo.core.ConcreteModel import z [as 別名]
def test_lmtd(self):
m = ConcreteModel()
m.x = Var(bounds=(0.1, 500), initialize=33.327)
m.y = Var(bounds=(0.1, 500), initialize=14.436)
m.z = Var(bounds=(0, 90), initialize=22.5653)
mc_expr = mc(m.z - (m.x * m.y * (m.x + m.y) / 2) ** (1/3))
self.assertAlmostEqual(mc_expr.convex(), -407.95444629965016)
self.assertAlmostEqual(mc_expr.lower(), -499.99999999999983)示例4: test_trig
# 需要導入模塊: from pyomo.core import ConcreteModel [as 別名]
# 或者: from pyomo.core.ConcreteModel import z [as 別名]
def test_trig(self):
m = ConcreteModel()
m.x = Var(bounds=(pi / 4, pi / 2), initialize=pi / 4)
mc_expr = mc(tan(atan((m.x))))
self.assertAlmostEqual(mc_expr.lower(), pi / 4)
self.assertAlmostEqual(mc_expr.upper(), pi / 2)
m.y = Var(bounds=(0, sin(pi / 4)), initialize=0)
mc_expr = mc(asin((m.y)))
self.assertEqual(mc_expr.lower(), 0)
self.assertAlmostEqual(mc_expr.upper(), pi / 4)
m.z = Var(bounds=(0, cos(pi / 4)), initialize=0)
mc_expr = mc(acos((m.z)))
self.assertAlmostEqual(mc_expr.lower(), pi / 4)
self.assertAlmostEqual(mc_expr.upper(), pi / 2)示例5: test_powers
# 需要導入模塊: from pyomo.core import ConcreteModel [as 別名]
# 或者: from pyomo.core.ConcreteModel import z [as 別名]
def test_powers(self):
m = ConcreteModel()
m.x = Var(bounds=(0, 2), initialize=1)
m.y = Var(bounds=(1e-4, 2), initialize=1)
with self.assertRaisesRegexp(MCPP_Error, "Log with negative values in range"):
mc(m.x ** 1.5)
mc_expr = mc(m.y ** 1.5)
self.assertAlmostEqual(mc_expr.lower(), 1e-4**1.5)
self.assertAlmostEqual(mc_expr.upper(), 2**1.5)
mc_expr = mc(m.y ** m.x)
self.assertAlmostEqual(mc_expr.lower(), 1e-4**2)
self.assertAlmostEqual(mc_expr.upper(), 4)
m.z = Var(bounds=(-1, 1), initialize=0)
mc_expr = mc(m.z ** 2)
self.assertAlmostEqual(mc_expr.lower(), 0)
self.assertAlmostEqual(mc_expr.upper(), 1)示例6: makeNestedDisjunctions
# 需要導入模塊: from pyomo.core import ConcreteModel [as 別名]
# 或者: from pyomo.core.ConcreteModel import z [as 別名]
def makeNestedDisjunctions():
m = ConcreteModel()
m.x = Var(bounds=(-9, 9))
m.z = Var(bounds=(0, 10))
m.a = Var(bounds=(0, 23))
def disjunct_rule(disjunct, flag):
m = disjunct.model()
if flag:
def innerdisj_rule(disjunct, flag):
m = disjunct.model()
if flag:
disjunct.c = Constraint(expr=m.z >= 5)
else:
disjunct.c = Constraint(expr=m.z == 0)
disjunct.innerdisjunct = Disjunct([0, 1], rule=innerdisj_rule)
@disjunct.Disjunction([0])
def innerdisjunction(b, i):
return [b.innerdisjunct[0], b.innerdisjunct[1]]
disjunct.c = Constraint(expr=m.a <= 2)
else:
disjunct.c = Constraint(expr=m.x == 2)
m.disjunct = Disjunct([0, 1], rule=disjunct_rule)
# I want a SimpleDisjunct with a disjunction in it too
def simpledisj_rule(disjunct):
m = disjunct.model()
@disjunct.Disjunct()
def innerdisjunct0(disjunct):
disjunct.c = Constraint(expr=m.x <= 2)
@disjunct.Disjunct()
def innerdisjunct1(disjunct):
disjunct.c = Constraint(expr=m.x >= 4)
disjunct.innerdisjunction = Disjunction(
expr=[disjunct.innerdisjunct0, disjunct.innerdisjunct1])
m.simpledisjunct = Disjunct(rule=simpledisj_rule)
m.disjunction = Disjunction(
expr=[m.simpledisjunct, m.disjunct[0], m.disjunct[1]])
return m