本文整理匯總了Python中pyomo.core.ConcreteModel.third_stage方法的典型用法代碼示例。如果您正苦於以下問題：Python ConcreteModel.third_stage方法的具體用法？Python ConcreteModel.third_stage怎麽用？Python ConcreteModel.third_stage使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類pyomo.core.ConcreteModel的用法示例。
在下文中一共展示了ConcreteModel.third_stage方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: build_model
# 需要導入模塊: from pyomo.core import ConcreteModel [as 別名]
# 或者: from pyomo.core.ConcreteModel import third_stage [as 別名]
def build_model():
"""
Base Model
Optimal solution:
Select units 1, 3, 8
Objective value -36.62
"""
m = ConcreteModel()
m.streams = RangeSet(25)
m.x = Var(m.streams, bounds=(0, 50), initialize=5)
m.stage1_split = Constraint(expr=m.x[1] == m.x[2] + m.x[4])
m.first_stage = Disjunction(expr=[
[
# Unit 1
m.x[2] == exp(m.x[3]) - 1,
m.x[4] == 0, m.x[5] == 0
],
[
# Unit 2
m.x[5] == log(m.x[4] + 1),
m.x[2] == 0, m.x[3] == 0
]
])
m.stage1_mix = Constraint(expr=m.x[3] + m.x[5] == m.x[6])
m.stage2_split = Constraint(expr=m.x[6] == sum(m.x[i] for i in (7, 9, 11, 13)))
m.second_stage = Disjunction(expr=[
[
# Unit 3
m.x[8] == 2 * log(m.x[7]) + 3,
m.x[7] >= 0.2,
] + [m.x[i] == 0 for i in (9, 10, 11, 12, 14, 15)],
[
# Unit 4
m.x[10] == 1.8 * log(m.x[9] + 4),
] + [m.x[i] == 0 for i in (7, 8, 11, 12, 14, 15)],
[
# Unit 5
m.x[12] == 1.2 * log(m.x[11]) + 2,
m.x[11] >= 0.001,
] + [m.x[i] == 0 for i in (7, 8, 9, 10, 14, 15)],
[
# Unit 6
m.x[15] == sqrt(m.x[14] - 3) * m.x[23] + 1,
m.x[14] >= 5, m.x[14] <= 20,
] + [m.x[i] == 0 for i in (7, 8, 9, 10, 11, 12)]
])
m.stage2_special_mix = Constraint(expr=m.x[14] == m.x[13] + m.x[23])
m.stage2_mix = Constraint(expr=sum(m.x[i] for i in (8, 10, 12, 15)) == m.x[16])
m.stage3_split = Constraint(expr=m.x[16] == sum(m.x[i] for i in (17, 19, 21)))
m.third_stage = Disjunction(expr=[
[
# Unit 7
m.x[18] == m.x[17] * 0.9,
] + [m.x[i] == 0 for i in (19, 20, 21, 22)],
[
# Unit 8
m.x[20] == log(m.x[19] ** 1.5) + 2,
m.x[19] >= 1,
] + [m.x[i] == 0 for i in (17, 18, 21, 22)],
[
# Unit 9
m.x[22] == log(m.x[21] + sqrt(m.x[21])) + 1,
m.x[21] >= 4,
] + [m.x[i] == 0 for i in (17, 18, 19, 20)]
])
m.stage3_special_split = Constraint(expr=m.x[22] == m.x[23] + m.x[24])
m.stage3_mix = Constraint(expr=m.x[25] == sum(m.x[i] for i in (18, 20, 24)))
m.obj = Objective(expr=-10 * m.x[25] + m.x[1])
return m