當前位置: 首頁>>代碼示例>>Python>>正文


Python MimicCore.session_for_tenant_id方法代碼示例

本文整理匯總了Python中mimic.core.MimicCore.session_for_tenant_id方法的典型用法代碼示例。如果您正苦於以下問題:Python MimicCore.session_for_tenant_id方法的具體用法?Python MimicCore.session_for_tenant_id怎麽用?Python MimicCore.session_for_tenant_id使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在mimic.core.MimicCore的用法示例。


在下文中一共展示了MimicCore.session_for_tenant_id方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: test_session_for_tenant_id

# 需要導入模塊: from mimic.core import MimicCore [as 別名]
# 或者: from mimic.core.MimicCore import session_for_tenant_id [as 別名]
 def test_session_for_tenant_id(self):
     """
     MimicCore.session_for_tenant_id will return a session that can be
     retrieved by tenant_id.
     """
     clock = Clock()
     core = MimicCore(clock, [])
     session = core.session_for_username_password("someuser", "testpass")
     session2 = core.session_for_tenant_id(session.tenant_id)
     self.assertIdentical(session, session2)
開發者ID:jirwin,項目名稱:mimic,代碼行數:12,代碼來源:test_core.py

示例2: test_generate_username_from_tenant_id

# 需要導入模塊: from mimic.core import MimicCore [as 別名]
# 或者: from mimic.core.MimicCore import session_for_tenant_id [as 別名]
 def test_generate_username_from_tenant_id(self):
     """
     MimicCore.session_for_tenant_id will create a new session with a
     synthetic username if no such tenant ID yet exists.
     """
     clock = Clock()
     core = MimicCore(clock, [])
     session = core.session_for_tenant_id("user_specified_tenant")
     session2 = core.session_for_username_password(session.username,
                                                   "testpass")
     self.assertIdentical(session, session2)
開發者ID:jirwin,項目名稱:mimic,代碼行數:13,代碼來源:test_core.py


注:本文中的mimic.core.MimicCore.session_for_tenant_id方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。