當前位置: 首頁>>代碼示例>>Python>>正文


Python MimicCore.session_for_impersonation方法代碼示例

本文整理匯總了Python中mimic.core.MimicCore.session_for_impersonation方法的典型用法代碼示例。如果您正苦於以下問題:Python MimicCore.session_for_impersonation方法的具體用法?Python MimicCore.session_for_impersonation怎麽用?Python MimicCore.session_for_impersonation使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在mimic.core.MimicCore的用法示例。


在下文中一共展示了MimicCore.session_for_impersonation方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: test_impersonation

# 需要導入模塊: from mimic.core import MimicCore [as 別名]
# 或者: from mimic.core.MimicCore import session_for_impersonation [as 別名]
 def test_impersonation(self):
     """
     MimicCore.session_for_impersonation will return a session that can be
     retrieved by token_id but not username.
     """
     clock = Clock()
     core = MimicCore(clock, [])
     A_LITTLE = 1234
     clock.advance(A_LITTLE)
     A_LOT = 65432
     a = core.session_for_impersonation("pretender", A_LOT)
     a_prime = core.session_for_impersonation("pretender", A_LOT)
     self.assertIdentical(a, a_prime)
     b = core.session_for_token(a.token)
     self.assertEqual(
         a.expires, datetime.utcfromtimestamp(A_LITTLE + A_LOT))
     self.assertIdentical(a, b)
     c = core.session_for_username_password("pretender", "not a password")
     self.assertNotIdentical(a, c)
     self.assertEqual(a.username, c.username)
     self.assertEqual(a.tenant_id, c.tenant_id)
開發者ID:jirwin,項目名稱:mimic,代碼行數:23,代碼來源:test_core.py


注:本文中的mimic.core.MimicCore.session_for_impersonation方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。