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Python Function.power方法代碼示例

本文整理匯總了Python中function.Function.power方法的典型用法代碼示例。如果您正苦於以下問題:Python Function.power方法的具體用法?Python Function.power怎麽用?Python Function.power使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在function.Function的用法示例。


在下文中一共展示了Function.power方法的4個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: test_split

# 需要導入模塊: from function import Function [as 別名]
# 或者: from function.Function import power [as 別名]
 def test_split(self):
     # If this ever breaks, we should solve the problem by writing a
     # new kind of Function that turns a lambda expression into a
     # Function.  That way, it will never be simplified.
     # f = x^2 + x
     f = Function.sum(Function.power(Function.identity(),
                                     Function.constant(2)),
                      Function.identity())
     # f(-1) = 0, f(0) = 0, f(-.5) = -.25
     # The range of f on [-1,0] is [-.25,0]
     # f([-1,0]) = [-1,1]
     # f([-1,-.5]) = [-.75,.5]
     # f([-.5,0]) = [-.5,.25]
     # This will never finish, since it asks for the exact bounds
     self.assertTrue(is_bounded(f, Interval(-1,0), Interval(-1/4,0))
                     is None)
     # g = 1/2*x^3-3/2*x
     g = Function.sum(Function.product(
             Function.constant(.5),
             Function.power(Function.identity(),
                            Function.constant(3))),
         Function.product(Function.constant(-1.5),
                          Function.identity()))
     self.assertEqual(is_bounded(g, Interval(-1.5,1.5), Interval(-.9,1)),
                      False)
     # This encounters a ValueError on the first split so should
     # return None
     h = Function.quotient(Function.constant(1), Function.identity())
     self.assertTrue(is_bounded(h, Interval(-1,1), Interval(-5,5)) is None)
開發者ID:bjthinks,項目名稱:grapher,代碼行數:31,代碼來源:slice.py

示例2: test_cubic_derivative

# 需要導入模塊: from function import Function [as 別名]
# 或者: from function.Function import power [as 別名]
 def test_cubic_derivative(self):
     a = cubic_derivative_approximation(
         Function.power(Function.identity(), Function.constant(3)),
         4, 10)
     self.assertAlmostEqual(a(0), 0)
     self.assertAlmostEqual(a(2), 8)
     self.assertAlmostEqual(a(5), 125)
     self.assertAlmostEqual(a(12), 1728)
     self.assertAlmostEqual(a(-3), -27)
開發者ID:bjthinks,項目名稱:grapher,代碼行數:11,代碼來源:approximate.py

示例3: test_approx

# 需要導入模塊: from function import Function [as 別名]
# 或者: from function.Function import power [as 別名]
    def test_approx(self):
        f = Function.identity()
        for a in approximate(f, 0, 1):
            self.assertTrue(isinstance(a, Function))
            self.assertTrue(isinstance(a, CubicSpline))
            # We may someday generate approximations that don't go through
            # the endpoints, and remove these tests.  Until then, they
            # help verify that the approximation formulas are correct.
            self.assertEqual(a(0.0), 0.0)
            self.assertEqual(a(1.0), 1.0)

        # (-x^2 - 1) ^ .5
        bad = Function.power(Function.sum(Function.product(
                Function.constant(-1),
                Function.power(Function.identity(), Function.constant(2))),
                                          Function.constant(-1)),
                             Function.constant(.5))
        self.assertEqual(list(approximate(bad, 0, 1)), [])
開發者ID:bjthinks,項目名稱:grapher,代碼行數:20,代碼來源:approximate.py

示例4: test_depth

# 需要導入模塊: from function import Function [as 別名]
# 或者: from function.Function import power [as 別名]
 def test_depth(self):
     f = Function.sum(Function.power(Function.identity(),
                                     Function.constant(2)),
                      Function.identity())
     # This requires splitting in half
     self.assertTrue(is_bounded(f, Interval(-1,0), Interval(-3/4,1/2), 1))
     self.assertEqual(is_bounded(f, Interval(-1,0), Interval(-3/4,1/2), 0),
                      None)
     # This requires 3 levels of recursion
     self.assertTrue(is_bounded(f, Interval(-1,0), Interval(-3/8,1/8), 3))
     self.assertEqual(is_bounded(f, Interval(-1,0), Interval(-3/8,1/8), 2),
                      None)
     # This requires 8 levels of recursion
     self.assertTrue(is_bounded(f, Interval(-1,0), Interval(-65/256,1/256),
                                8))
     self.assertEqual(is_bounded(f, Interval(-1,0), Interval(-65/256,1/256),
                                 7), None)
開發者ID:bjthinks,項目名稱:grapher,代碼行數:19,代碼來源:slice.py


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