本文整理匯總了Python中admit.util.AdmitLogging.AdmitLogging.getEffectiveLevel方法的典型用法代碼示例。如果您正苦於以下問題：Python AdmitLogging.getEffectiveLevel方法的具體用法？Python AdmitLogging.getEffectiveLevel怎麽用？Python AdmitLogging.getEffectiveLevel使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類admit.util.AdmitLogging.AdmitLogging的用法示例。
在下文中一共展示了AdmitLogging.getEffectiveLevel方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: test_effectiveLevel
# 需要導入模塊: from admit.util.AdmitLogging import AdmitLogging [as 別名]
# 或者: from admit.util.AdmitLogging.AdmitLogging import getEffectiveLevel [as 別名]
def test_effectiveLevel(self):
msg = "unit_test_levels_message"
# check that the logging level is what is expected
level = Alogging.getEffectiveLevel()
self.assertTrue(level == self.level)
# set the level to a new value and check again
Alogging.setLevel(50)
level = Alogging.getEffectiveLevel()
self.assertTrue(level == 50)
# log an info message which is below the logging level, this message should not appear
# in the logs
Alogging.info(msg)
found = False
r = open(self.logfile, 'r')
for line in r.readlines():
if msg in line:
if(self.verbose):
print "\nFound message >", line
found = True
break
r.close()
self.assertFalse(found)
Alogging.setLevel(self.level)
# reset the logging level
msg += "2"
# log an info message, which is now above the logging level, this message should appear
# in the logs
Alogging.info(msg)
found = False
r = open(self.logfile, 'r')
for line in r.readlines():
if msg in line:
if(self.verbose):
print "\nFound message >", line
found = True
r.close()
break
self.assertTrue(found)