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Python Card.getKINames方法代碼示例

本文整理匯總了Python中Card.getKINames方法的典型用法代碼示例。如果您正苦於以下問題:Python Card.getKINames方法的具體用法?Python Card.getKINames怎麽用?Python Card.getKINames使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Card的用法示例。


在下文中一共展示了Card.getKINames方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: range

# 需要導入模塊: import Card [as 別名]
# 或者: from Card import getKINames [as 別名]
import Card
import CurrentScreen
import EnumsCards

# 0: Player, 1: KI
numberOf = []
startPlayer = 0
numberOf.append(int(input("How many players? ")))
numberOf.append(int(input("How many computers? ")))
# direction 1: clockwise, -1: counter-clockwise
pointsOfPlayers = Card.initPointsOfPlayers(numberOf[0] + numberOf[1])
# drawCards[1] 0=> + Cards not drawn, 1=> are drawn
drawCards = [0, 0]
names = Card.getNames(numberOf[0])
names.extend(Card.getKINames(numberOf[1]))
while(Card.someHasEnoughtPoints(pointsOfPlayers) == -1):
    cardStack = Card.initStackOfCards()
    Card.shuffleDeckofCards(cardStack)
    handsOfCards = []
    for player in range((numberOf[0] + numberOf[1])):
        handsOfCards.append(Card.initHand(cardStack))
    direction = 1
    otherColor = -1
    lastCard = Card.drawCard(cardStack)
    whichPlayer = startPlayer % (numberOf[0]+numberOf[1])
    startPlayer += 1
    if lastCard.getValue() == "draw2":
        if lastCard.backInDeck == 1:
            drawCards[0] = 0
        else:
            drawCards[0] += 2
開發者ID:NWuensche,項目名稱:UNOinPython,代碼行數:33,代碼來源:main.py


注:本文中的Card.getKINames方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。