本文整理匯總了PHP中Zend_Acl_Resource_Interface::getUserById方法的典型用法代碼示例。如果您正苦於以下問題：PHP Zend_Acl_Resource_Interface::getUserById方法的具體用法？PHP Zend_Acl_Resource_Interface::getUserById怎麽用？PHP Zend_Acl_Resource_Interface::getUserById使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Zend_Acl_Resource_Interface的用法示例。
在下文中一共展示了Zend_Acl_Resource_Interface::getUserById方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: assert
/**
* This assertion should receive the actual User objects.
*
* @param Zend_Acl $acl
* @param Zend_Acl_Role_Interface $user
* @param Zend_Acl_Resource_Interface $model
* @param $privilege
* @return bool
*/
public function assert(Zend_Acl $acl, Zend_Acl_Role_Interface $user = null, Zend_Acl_Resource_Interface $model = null, $privilege = null)
{
$request = Zend_Controller_Front::getInstance()->getRequest();
// have to hack this because of the 'oneitem' route all controller/action combo's will execute this assertion
// @todo: change this in the oneitem route somehow?
if ($request->getControllerName() !== 'user') {
return true;
}
$param = $request->getParam('id', null);
if (!$param) {
return true;
}
// perform check
if ($model->getUserById($param)->hasRole(array('presenter', 'chair'))) {
return true;
} else {
return false;
}
}