本文整理匯總了PHP中Zend_Acl_Resource_Interface::getRole方法的典型用法代碼示例。如果您正苦於以下問題：PHP Zend_Acl_Resource_Interface::getRole方法的具體用法？PHP Zend_Acl_Resource_Interface::getRole怎麽用？PHP Zend_Acl_Resource_Interface::getRole使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Zend_Acl_Resource_Interface的用法示例。
在下文中一共展示了Zend_Acl_Resource_Interface::getRole方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: assert
/**
* Returns true if and only if the assertion conditions are met
*
* This method is passed the ACL, Role, Resource, and privilege to which
* the authorization query applies. If the $role, $resource, or $privilege
* parameters are null, it means that the query applies to all Roles,
* Resources, or privileges, respectively.
*
* @param Zend_Acl $acl
* @param Zend_Acl_Role_Interface $role
* @param Zend_Acl_Resource_Interface $resource
* @param string $privilege
* @return boolean
*/
public function assert(Zend_Acl $acl, Zend_Acl_Role_Interface $role = null, Zend_Acl_Resource_Interface $resource = null, $privilege = null)
{
// We need specific objects to check against each other
if (NULL === $role || NULL === $resource) {
return false;
}
// Ensure we're handled User models
if (!$role instanceof UserModel) {
throw new Exception('Role must be an instance of UserModel');
}
if (!$resource instanceof UserModel) {
throw new Exception('Resource must be an instance of UserModel');
}
$resourceRole = $resource->getRole();
return $resourceRole === "admin" || $resourceRole === "admin-smip";
}