本文整理匯總了C#中System.Complex.SquareRoot方法的典型用法代碼示例。如果您正苦於以下問題：C# Complex.SquareRoot方法的具體用法？C# Complex.SquareRoot怎麽用？C# Complex.SquareRoot使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類System.Complex的用法示例。
在下文中一共展示了Complex.SquareRoot方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的C#代碼示例。
示例1: CanComputeSquareRoot
public void CanComputeSquareRoot()
{
var complex = new Complex(1.19209289550780998537e-7, 1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(
new Complex(0.00037933934912842666, 0.00015712750315077684), complex.SquareRoot(), 15);
complex = new Complex(0.0, 1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(
new Complex(0.00024414062499999973, 0.00024414062499999976), complex.SquareRoot(), 15);
complex = new Complex(0.0, -1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(
new Complex(0.00024414062499999973, -0.00024414062499999976), complex.SquareRoot(), 15);
complex = new Complex(0.0, 0.5);
AssertHelpers.AlmostEqual(new Complex(0.5, 0.5), complex.SquareRoot(), 15);
complex = new Complex(0.0, -0.5);
AssertHelpers.AlmostEqual(new Complex(0.5, -0.5), complex.SquareRoot(), 15);
complex = new Complex(0.0, -8.388608e6);
AssertHelpers.AlmostEqual(new Complex(2048.0, -2048.0), complex.SquareRoot(), 15);
complex = new Complex(8.388608e6, 1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(new Complex(2896.3093757400989, 2.0579515874459933e-11), complex.SquareRoot(), 15);
complex = new Complex(0.0, 0.0);
AssertHelpers.AlmostEqual(Complex.Zero, complex.SquareRoot(), 15);
}