本文整理匯總了C#中System.Complex.Root方法的典型用法代碼示例。如果您正苦於以下問題：C# Complex.Root方法的具體用法？C# Complex.Root怎麽用？C# Complex.Root使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類System.Complex的用法示例。
在下文中一共展示了Complex.Root方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的C#代碼示例。
示例1: CanComputeRoot
public void CanComputeRoot()
{
var a = new Complex(1.19209289550780998537e-7, 1.19209289550780998537e-7);
var b = new Complex(1.19209289550780998537e-7, 1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(new Complex(0.0, 0.0), a.Root(b), 15);
a = new Complex(0.0, -1.19209289550780998537e-7);
b = new Complex(0.0, 0.5);
AssertHelpers.AlmostEqual(new Complex(0.038550761943650161, 0.019526430428319544), a.Root(b), 15);
a = new Complex(0.0, 0.5);
b = new Complex(0.0, -0.5);
AssertHelpers.AlmostEqual(new Complex(0.007927894711475968, -0.042480480425152213), a.Root(b), 15);
a = new Complex(0.0, -0.5);
b = new Complex(0.0, 1.0);
AssertHelpers.AlmostEqual(new Complex(0.15990905692806806, 0.13282699942462053), a.Root(b), 15);
a = new Complex(0.0, 2.0);
b = new Complex(0.0, -2.0);
AssertHelpers.AlmostEqual(new Complex(0.42882900629436788, 0.15487175246424678), a.Root(b), 15);
a = new Complex(0.0, -8.388608e6);
b = new Complex(1.19209289550780998537e-7, 0.0);
AssertHelpers.AlmostEqual(new Complex(double.PositiveInfinity, double.NegativeInfinity), a.Root(b), 15);
}