Python Sympy Subset.rank_lexicographic()用法及代码示例

Subset.rank_lexicographic()：rank_lexicographic()是一个sympy Python库函数，它返回该子集的字典顺序。

用法：

sympy.combinatorics.subset.Subset.rank_lexicographic()

返回：
该子集的字典顺序。

代码1：rank_lexicographic()示例

# Python code explaining 
# SymPy.Subset.rank_lexicographic() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.rank_lexicographic() 
  
# Creating Subset 
a = Subset(['c', 'd'], ['geek', 'for', 'c', 'd']) 
  
# rank_lexicographic value 
print ("Subset a rank_lexicographic : ", a.rank_lexicographic)

输出：

Subset a rank_lexicographic : 14

代码2：rank_lexicographic()示例

# Python code explaining 
# SymPy.Subset.rank_lexicographic() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.rank_lexicographic() 
  
# Creating Subset 
a = Subset([2, 3, 4], [1, 2, 3, 4, 5]) 
  
# rank_lexicographic value 
print ("Subset a rank_lexicographic : ", a.rank_lexicographic)

输出：

Subset a rank_lexicographic : 19

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注：本文由纯净天空筛选整理自noobestars101大神的英文原创作品 SymPy | Subset.rank_lexicographic() in Python。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。