Permutation.unrank_lex():unrank_lex()是一个sympy Python库函数,它返回词法排列不排序。
用法: sympy.combinatorics.permutations.Permutation.unrank_lex()
返回:词典排列置换
代码1:unrank_lex()示例
# Python code explaining
# SymPy.Permutation.unrank_lex()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.unrank_lex() method
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
b = Permutation([1, 3, 5, 4, 2, 0])
size = 2
rank = 5
print ("Permutation a - unrank_lex form : ", a.unrank_lex(size, rank))
print ("Permutation b - unrank_lex form : ", b.unrank_lex(size, 2))
输出:
Permutation a – unrank_lex form : (0 1)
Permutation b – unrank_lex form : (1)
代码2:unrank_lex()示例
# Python code explaining
# SymPy.Permutation.unrank_lex()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.unrank_lex() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
print ("Permutation a - unrank_lex form : ", a.unrank_lex(5, 2))
输出:
Permutation a – unrank_lex form : (4)(2 3)
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注:本文由纯净天空筛选整理自noobestars101大神的英文原创作品 SymPy | Permutation.unrank_lex() in Python。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。