Python Sympy Permutation.next_trotterjohnson()用法及代码示例

Permutation.next_trotterjohnson()：next_trotterjohnson()是一个sympy Python库函数，它以Trotter-Johnson顺序返回下一个排列。如果self是最后一个排列，则返回None。

用法： sympy.combinatorics.permutations.Permutation.next_trotterjohnson()

返回：Trotter-Johnson顺序中的下一个排列

代码1：next_trotterjohnson()示例

# Python code explaining 
# SymPy.Permutation.next_trotterjohnson() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from  
# sympy.combinatorics.permutations.Permutation.next_trotterjohnson() method  
  
# creating Permutation 
a = Permutation([[2, 0], [3, 1]]) 
  
b = Permutation([1, 3, 5, 4, 2, 0]) 
  
  
print ("Permutation a - next_trotterjohnson form : ", a.next_trotterjohnson()) 
print ("Permutation b - next_trotterjohnson form : ", b.next_trotterjohnson())

输出：

Permutation a – next_trotterjohnson form : (0 3 1 2)
Permutation b – next_trotterjohnson form : (0 1 5)(2 3 4)

代码2：next_trotterjohnson()示例– 2D排列

# Python code explaining 
# SymPy.Permutation.next_trotterjohnson() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from  
# sympy.combinatorics.permutations.Permutation.next_trotterjohnson() method  
  
# creating Permutation 
a = Permutation([[2, 4, 0],  
                 [3, 1, 2], 
                 [1, 5, 6]]) 
  
  
print ("Permutation a - next_trotterjohnson form : ", a.next_trotterjohnson())

输出：

Permutation a – next_trotterjohnson form : (6)(0 3 5 1 2 4)

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注：本文由纯净天空筛选整理自noobestars101大神的英文原创作品 SymPy | Permutation.next_trotterjohnson() in Python。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。