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C++ std::divides用法及代码示例


用于执行除法的函数对象。在两个T类型的实例上有效地调用operator /。

用法:


template  struct divides:binary_function  
{
    T operator() (const T& x, const T& y) const {return x/y;}
};

Template Parameters:
T - Type of the arguments and return type of the functional call.
    The type shall support the operation (operator /).

Member types:
x:Type of the first argument in member operator()
y:Type of the second argument in member operator()
result_type:Type returned by member operator()

例:


// C++ program to illustrate std::divides 
// by dividing the respective elements of 2 arrays 
#include <iostream> // std::cout 
#include <functional> // std::divides 
#include <algorithm> // std::transform 
  
int main() 
{ 
    // First array 
    int first[] = { 10, 20, 30, 40, 50 }; 
  
    // Second array 
    int second[] = { 1, 2, 3, 4, 5 }; 
  
    // Result array 
    int results[5]; 
  
    // std::transform applies std::divides to the whole array 
    std::transform(first, first + 5, second, results, std::divides<int>()); 
  
    // Printing the result array 
    for (int i = 0; i < 5; i++) 
        std::cout << results[i] << " "; 
  
    return 0; 
}

输出:

10 10 10 10 10

另一个例子:

// C++ program to illustrate std::divides 
// by dividing all array elements with a number 
#include <bits/stdc++.h> 
  
int main() 
{ 
    // Array with elements to be divided 
    int arr[] = { 10, 10 }; 
  
    // size of array 
    int size = sizeof(arr) / sizeof(arr[0]); 
  
    // Variable with which array is to be divided 
    int num = 100; 
  
    // Variable to store result 
    int result; 
  
    // using std::accumulate to perform division on array with num 
    // using std::divides 
    result = std::accumulate(arr, arr + size, num, std::divides<int>()); 
  
    // Printing the result 
    std::cout << "The result of (100 / 10) / 10 is " << result; 
  
    return 0; 
}

输出:

The result of (100 / 10) / 10 is 1


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注:本文由纯净天空筛选整理自 std::divides in C++。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。