返回对指定位置pos处字符的引用。该函数自动检查pos是否是字符串中字符的有效位置(即pos是否小于字符串长度),如果不是,则抛出out_of_range异常。
用法:
reference at (size_type pos); const_reference at (size_type pos) const; 参数: pos - position of the character to return Return value: Reference to the requested character Exceptions: Throws std::out_of_range if pos >= size().
// CPP program to access a character through
// std::basic_string::at
#include <stdexcept>
#include <iostream>
int main()
{
// String with valid indices from 0 to 2
std::string str = "abc";
// Printing size of string
std::cout << "string size = " << str.size() << '\n';
// Accessing out of bounds index
try
{
str.at(4) = 't';
}
// If error is generated, it is caught
catch (std::out_of_range const& error)
{
std::cout << error.what() << '\n';
}
}
输出:
string size = 3 basic_string::at:__n (which is 4) >= this->size() (which is 3)
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注:本文由纯净天空筛选整理自 std::basic_string::at in C++。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。