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Ruby Date gregorian?用法及代码示例


Date#gregorian?()是一个Date类方法,该方法检查日期是在日历改革之日还是之后。

用法:Date.gregorian?()

参数:日期值


返回:true-如果日期在日历改革之日或之后,否则返回false。

范例1:

# Ruby code for Date.gregorian?() method 
  
# loading date 
require 'date'
  
# declaring Date  
a = Date.new(2019, 1, 1) 
  
# declaring Date 
b = Date.jd(2452004) 
  
# declaring Date 
c = Date.ordinal(2019, 12) 
  
# Date  
puts "Date a:#{a}\n\n"
puts "Date b:#{b}\n\n"
puts "Date c:#{c}\n\n\n\n"
  
  
# gregorian? form  
puts "Date a gregorian? form:#{a.gregorian?}\n\n"
puts "Date b gregorian? form:#{b.gregorian?}\n\n"
puts "Date c gregorian? form:#{c.gregorian?}\n\n"

输出:

Date a:2019-01-01

Date b:2001-04-04

Date c:2019-01-12



Date a gregorian? form:true

Date b gregorian? form:true

Date c gregorian? form:true

范例2:

# Ruby code for Date.gregorian?() method 
  
# loading date 
require 'date'
  
# declaring Date  
a = Date.parse('2019-01-01') 
  
# declaring Date 
b = Date.strptime('03-12-2019', '%d-%m-%Y') 
  
# declaring Date 
c = Date.commercial(2019, 5, 6) 
  
# Date  
puts "Date a:#{a}\n\n"
puts "Date b:#{b}\n\n"
puts "Date c:#{c}\n\n\n\n"
  
  
# gregorian? form  
puts "Date a gregorian? form:#{a.gregorian?}\n\n"
puts "Date b gregorian? form:#{b.gregorian?}\n\n"
puts "Date c gregorian? form:#{c.gregorian?}\n\n"

输出:

Date a:2019-01-01

Date b:2019-12-03

Date c:2019-02-02



Date a gregorian? form:true

Date b gregorian? form:true

Date c gregorian? form:true



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注:本文由纯净天空筛选整理自Kirti_Mangal大神的英文原创作品 Ruby | Date gregorian? function。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。