Date#gregorian?()是一个Date类方法,该方法检查日期是在日历改革之日还是之后。
用法:Date.gregorian?()
参数:日期值
返回:true-如果日期在日历改革之日或之后,否则返回false。
范例1:
# Ruby code for Date.gregorian?() method
# loading date
require 'date'
# declaring Date
a = Date.new(2019, 1, 1)
# declaring Date
b = Date.jd(2452004)
# declaring Date
c = Date.ordinal(2019, 12)
# Date
puts "Date a:#{a}\n\n"
puts "Date b:#{b}\n\n"
puts "Date c:#{c}\n\n\n\n"
# gregorian? form
puts "Date a gregorian? form:#{a.gregorian?}\n\n"
puts "Date b gregorian? form:#{b.gregorian?}\n\n"
puts "Date c gregorian? form:#{c.gregorian?}\n\n"
输出:
Date a:2019-01-01 Date b:2001-04-04 Date c:2019-01-12 Date a gregorian? form:true Date b gregorian? form:true Date c gregorian? form:true
范例2:
# Ruby code for Date.gregorian?() method
# loading date
require 'date'
# declaring Date
a = Date.parse('2019-01-01')
# declaring Date
b = Date.strptime('03-12-2019', '%d-%m-%Y')
# declaring Date
c = Date.commercial(2019, 5, 6)
# Date
puts "Date a:#{a}\n\n"
puts "Date b:#{b}\n\n"
puts "Date c:#{c}\n\n\n\n"
# gregorian? form
puts "Date a gregorian? form:#{a.gregorian?}\n\n"
puts "Date b gregorian? form:#{b.gregorian?}\n\n"
puts "Date c gregorian? form:#{c.gregorian?}\n\n"
输出:
Date a:2019-01-01 Date b:2019-12-03 Date c:2019-02-02 Date a gregorian? form:true Date b gregorian? form:true Date c gregorian? form:true
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注:本文由纯净天空筛选整理自Kirti_Mangal大神的英文原创作品 Ruby | Date gregorian? function。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。