regex_iterator()是C++中BiDirectionalIterator类的函数。此方法返回一个迭代器类型,以迭代序列中同一正则表达式模式的不同匹配。
用法:
template< class BidirectionalIterator, class CharT = typename std::iterator_traits::value_type, class Traits = std::regex_traits > class regex_iterator
C++ 14语法
template <class BidirectionalIterator, class charT=typename iterator_traits::value_type, class traits=regex_traits > class regex_iterator;
C++ 11语法:
template <class BidirectionalIterator, class charT=typename iterator_traits::value_type, class traits=regex_traits > class regex_iterator;
参数:此方法接受以下参数:
- BidirectionalIterator:迭代目标字符序列。
- 字符:这是一个字符类型。
- traits:这是正则表达式特征类型。
返回值:此方法返回带有结果序列的字符串对象。
以下示例说明了regex_iterator()方法:
例:
#include <iostream>
#include <iterator>
#include <regex>
#include <string>
using namespace std;
int main()
{
const string
strg
= "Geeksforgeeks welcome geeks.";
regex words_regex("[^\\s]+");
auto
words_begin
= sregex_iterator(
strg.begin(),
strg.end(),
words_regex);
auto words_end = sregex_iterator();
cout << "Trying to find words"
<< " using regex_iterator:\n\n";
cout << "Number of words found:"
<< distance(words_begin, words_end);
cout << "\n\nThe words are:\n";
for (sregex_iterator k = words_begin;
k != words_end;
++k) {
smatch match = *k;
string match_str = match.str();
cout << match_str
<< endl;
}
}
输出:
Trying to find words using regex_iterator: Number of words found:3 The words are: Geeksforgeeks welcome geeks.
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注:本文由纯净天空筛选整理自Pushpanjali chauhan大神的英文原创作品 regex_iterator() function in C++ STL。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。