Python支持面向对象的编程,因此可以使用python创建类。有时,必须了解mid-program哪些对象属于哪个类。 isinstance()执行此函数,因此使我们的编程任务更加容易。
语法:isinstance(obj,class)
参数:
obj:是否需要作为类的一部分进行检查的对象。
class:类/类型/类或类型的元组,需要对照该对象进行检查。
返回:是,如果通过单个类,则对象属于给定的类/类型;如果通过类/类型的元组,则对象属于任何类/类型,否则返回False。如果提到的有效类类型以外的任何其他类型,则引发TypeError。
代码1:演示isinstance对于本机类型的工作。
# Python 3 code to demonstrate
# working of isinstance()
# with native types
# initializing native types
test_int = 5
test_str = "GeeksforGeeks"
test_list = [1, 2, 3]
# testing with isinstance
print ("Is test_int integer?:" + str(isinstance(test_int, int)))
print ("Is test_int string?:" + str(isinstance(test_int, str)))
print ("Is test_str string?:" + str(isinstance(test_str, str)))
print ("Is test_list integer?:" + str(isinstance(test_list, int)))
print ("Is test_list list?:" + str(isinstance(test_list, list)))
# testing with tuple
print ("Is test_int integer or list or string?:"
+ str(isinstance(test_int, (list, str, int))))
print ("Is test_list string or tuple?:"
+ str(isinstance(test_list, (str, tuple))))
输出:
Is test_int integer?:True Is test_int string?:False Is test_str string?:True Is test_list integer?:False Is test_list list?:True Is test_int integer or list or string?:True Is test_list string or tuple?:False
代码#2:演示isinstance()与对象的结合使用
# Python 3 code to demonstrate
# working of isinstance()
# with objects
# declaring classes
class gfg1:
a = 10
# inherited class
class gfg2(gfg1):
strng = 'GeeksforGeeks'
# initializing objects
obj1 = gfg1()
obj2 = gfg2()
# checking istances
print ("Is obj1 instance of gfg1?:" + str(isinstance(obj1, gfg1)))
print ("Is obj2 instance of gfg2?:" + str(isinstance(obj2, gfg2)))
print ("Is obj1 instance of gfg2?:" + str(isinstance(obj1, gfg2)))
# check inhertance case
# return true
print ("Is obj2 instance of gfg1?:" + str(isinstance(obj2, gfg1)))
输出:
Is obj1 instance of gfg1?:True Is obj2 instance of gfg2?:True Is obj1 instance of gfg2?:False Is obj2 instance of gfg1?:True
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注:本文由纯净天空筛选整理自manjeet_04大神的英文原创作品 Python | isinstance() method。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。