Python Tweepy API.show_friendship()用法及代码示例

Twitter是一种流行的社交网络，用户在其中共享称为推文的消息。 Twitter允许我们使用Twitter API或Tweepy挖掘任何用户的数据。数据将是从用户提取的推文。首先要做的是从每个用户都可以轻松获得Twitter开发人员的使用者 key ，使用者 key ，访问 key 和访问 key 。这些 key 将帮助API进行身份验证。

API.show_friendship()

的show_friendship()方法APITweepy模块中的class用于获取两个用户之间的详细关系。

用法：API.show_friendship(source_id / source_screen_name, target_id / target_screen_name)

参数：

source_id:指定用户的ID 1。
source_screen_name:指定用户的屏幕名称1。
target_id:指定用户的ID 2。
target_screen_name:指定用户的屏幕名称2。

返回值：友谊类的对象

范例1：通过使用屏幕名称分析友谊。

# import the module 
import tweepy 
  
# assign the values accordingly 
consumer_key = "" 
consumer_secret = "" 
access_token = "" 
access_token_secret = "" 
  
# authorization of consumer key and consumer secret 
auth = tweepy.OAuthHandler(consumer_key, consumer_secret) 
  
# set access to user's access key and access secret  
auth.set_access_token(access_token, access_token_secret) 
  
# calling the api  
api = tweepy.API(auth) 
  
# screen name of the account 1 
source_screen_name = "Twitter"
  
# screen name of the account 2 
target_screen_name = "TwitterIndia"
  
# getting the friendship details 
friendship = api.show_friendship(source_screen_name = source_screen_name, target_screen_name = target_screen_name) 
  
print("Is " + friendship[0].screen_name + " followed by " + friendship[1].screen_name, end = "?:") 
if friendship[0].followed_by == False:
    print("No") 
else:
    print("Yes") 
  
print("Is " + friendship[0].screen_name + " following " + friendship[1].screen_name, end = "?:") 
if friendship[0].following == False:
    print("No") 
else:
    print("Yes")

输出：

Is Twitter followed by TwitterIndia?:Yes
Is Twitter following TwitterIndia?:No

范例2：通过使用用户ID分析友谊。

# user ID of the account 1 
source_id = 14230524
  
# user ID of the account 2 
target_id = 34507480
  
# getting the friendship details 
friendship = api.show_friendship(source_id = source_id, target_id = target_id) 
  
print("The sceen name of user 1 is:" + friendship[0].screen_name) 
print("The sceen name of user 2 is:" + friendship[1].screen_name) 
  
print("Is " + friendship[0].screen_name + " followed by " + friendship[1].screen_name, end = "?:") 
if friendship[0].followed_by == False:
    print("No") 
else:
    print("Yes") 
  
print("Is " + friendship[0].screen_name + " following " + friendship[1].screen_name, end = "?:") 
if friendship[0].following == False:
    print("No") 
else:
    print("Yes")

输出：

The sceen name of user 1 is:ladygaga
The sceen name of user 2 is:ArianaGrande
Is ladygaga followed by ArianaGrande?:Yes
Is ladygaga following ArianaGrande?:No

相关用法

注：本文由纯净天空筛选整理自Yash_R大神的英文原创作品 Python – API.show_friendship() in Tweepy。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。