numpy.iscomplexobj(array)：此逻辑函数有助于检查数组的复杂类型或复数数组。即使虚部等于零，它也被视为复杂对象。
参数：
array :[array_like]Input array or object whose elements, we need to test.
返回：
True, if the input array has a complex element; otherwise False
代码1：
# Python program explaining
# iscomplexobj() function
import numpy as np
in_array = [1, 3, 5, 4]
print ("Input array:", in_array)
output_value = np.iscomplexobj(in_array)
print ("\nIs complex:", output_value)输出：
Input array: [1, 3, 5, 4] Is complex: False
代码2：
# Python Program illustrating
# numpy.iscomplexobj() method
import numpy as geek
# Returns True/False value for each element
a = geek.arange(20).reshape(5, 4)
print("Is complex:\n", geek.iscomplexobj(a))
# Returns True/False value as ans
# because we have mentioned dtpe in the begining
b = geek.arange(20).reshape(5, 4).dtype = complex
print("\n",b)
print("\nIs complex:", geek.iscomplexobj(b))
b = [[1j],
[3]]
print("\nIs complex:\n", geek.iscomplexobj(b))输出：
Is complex: False class 'complex' Is complex: False Is complex: True
相关用法
注：本文由纯净天空筛选整理自Mohit Gupta_OMG 大神的英文原创作品 numpy.iscomplexobj() in Python。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。