numpy.core.defchararray.count(arr，substring，start = 0，end = None)：在指定范围内不重复出现的子字符串的计数。
参数:
arr : array-like or string to be searched.
substring : substring to search for.
start, end: [int, optional] Range to search in.返回: An integer array with the number of non-overlapping occurrences of sub-string.
代码1：
# Python Program illustrating
# numpy.char.count() method
import numpy as np
# 2D array
arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
print ("arr:", arr)
print ("Count of 'tt'", np.char.count(arr, 'tt'))
print ("Count of 'tt'", np.char.count(arr, 'tt', start = 0))
print ("Count of 'tt'", np.char.count(arr, 'tt', start = 8))输出：
arr: ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz'] Count of 'tt' [2 2 1 0] Count of 'tt' [2 2 1 0] Count of 'tt' [1 2 1 0]
代码2：
# Python Program illustrating
# numpy.char.count() method
import numpy as np
# 2D array
arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
print ("arr:", arr)
print ("Count of 'Aa'", np.char.count(arr, 'Aa'))
print ("Count of 'Aa'", np.char.count(arr, 'Aa', start = 8))输出：
arr: ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz'] Count of 'Aa' [1 1 1 1] Count of 'Aa' [1 0 0 0]
相关用法
注：本文由纯净天空筛选整理自Mohit Gupta_OMG 大神的英文原创作品 numpy.count() in Python。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。