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Java LocalTime minusSeconds()用法及代码示例


LocalTime类的minusSeconds()方法用于从此LocalTime中减去指定的秒数,然后将结果作为LocalTime对象返回。这一瞬间是一成不变的。计算大约在午夜结束。

用法:

public LocalTime minusSeconds(long SecondsToSubtract)

参数:此方法接受单个参数SecondsToSubtract,该参数是要减去的Seconds的值,它可以是负值。


返回值:此方法基于此时间返回LocalTime并减去Seconds。

以下示例程序旨在说明minusSeconds()方法:

示例1:

// Java program to demonstrate 
// LocalTime.minusSeconds() method 
  
import java.time.*; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
  
        // create a LocalTime object 
        LocalTime time 
            = LocalTime.parse("19:34:50.63"); 
  
        // print LocalTime 
        System.out.println("LocalTime before subtraction: "
                           + time); 
  
        // subtract 200 Seconds using minusSeconds() 
        LocalTime value = time.minusSeconds(200); 
  
        // print result 
        System.out.println("LocalTime after subtraction: "
                           + value); 
    } 
}
输出:
LocalTime before subtraction: 19:34:50.630
LocalTime after subtraction: 19:31:30.630

示例2:

// Java program to demonstrate 
// LocalTime.minusSeconds() method 
  
import java.time.*; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
  
        // create a LocalTime object 
        LocalTime time 
            = LocalTime.parse("01:00:01"); 
  
        // print LocalTime 
        System.out.println("LocalTime before subtraction: "
                           + time); 
  
        // subtract -3400 Seconds using minusSeconds() 
        LocalTime value = time.minusSeconds(-3400); 
  
        // print result 
        System.out.println("LocalTime after subtraction: "
                           + value); 
    } 
}
输出:
LocalTime before subtraction: 01:00:01
LocalTime after subtraction: 01:56:41

参考文献: https://docs.oracle.com/javase/10/docs/api/java/time/LocalTime.html#minusSeconds(long)



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