LocalTime类的minusSeconds()方法用于从此LocalTime中减去指定的秒数,然后将结果作为LocalTime对象返回。这一瞬间是一成不变的。计算大约在午夜结束。
用法:
public LocalTime minusSeconds(long SecondsToSubtract)
参数:此方法接受单个参数SecondsToSubtract,该参数是要减去的Seconds的值,它可以是负值。
返回值:此方法基于此时间返回LocalTime并减去Seconds。
以下示例程序旨在说明minusSeconds()方法:
示例1:
// Java program to demonstrate
// LocalTime.minusSeconds() method
import java.time.*;
public class GFG {
public static void main(String[] args)
{
// create a LocalTime object
LocalTime time
= LocalTime.parse("19:34:50.63");
// print LocalTime
System.out.println("LocalTime before subtraction: "
+ time);
// subtract 200 Seconds using minusSeconds()
LocalTime value = time.minusSeconds(200);
// print result
System.out.println("LocalTime after subtraction: "
+ value);
}
}
输出:
LocalTime before subtraction: 19:34:50.630 LocalTime after subtraction: 19:31:30.630
示例2:
// Java program to demonstrate
// LocalTime.minusSeconds() method
import java.time.*;
public class GFG {
public static void main(String[] args)
{
// create a LocalTime object
LocalTime time
= LocalTime.parse("01:00:01");
// print LocalTime
System.out.println("LocalTime before subtraction: "
+ time);
// subtract -3400 Seconds using minusSeconds()
LocalTime value = time.minusSeconds(-3400);
// print result
System.out.println("LocalTime after subtraction: "
+ value);
}
}
输出:
LocalTime before subtraction: 01:00:01 LocalTime after subtraction: 01:56:41
参考文献: https://docs.oracle.com/javase/10/docs/api/java/time/LocalTime.html#minusSeconds(long)
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