Java java.util.regex.Matcher.requireEnd()用法及代码示例

描述

这个java.util.regex.Matcher.requireEnd()如果更多输入可以将正匹配更改为负匹配，则方法返回 true。

声明

以下是声明java.util.regex.Matcher.requireEnd()方法。

public boolean requireEnd()

返回值

当且仅当更多输入可以将正匹配变为负匹配时为真。

示例

下面的例子展示了 java.util.regex.Matcher.requireEnd() 方法的用法。

package com.tutorialspoint;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MatcherDemo {
   private static String REGEX = "(a*b)(foo)";
   private static String INPUT = "aabfooaabfooabfoob";
   private static String REPLACE = "-";
   
   public static void main(String[] args) {
      Pattern pattern = Pattern.compile(REGEX);
      
      // get a matcher object
      Matcher matcher = pattern.matcher(INPUT);
      
      while(matcher.find()) {
         //Prints the offset after the last character matched.
         System.out.println("First Capturing Group, (a*b) Match String end():"+matcher.end());   
         System.out.println("requireEnd():"+matcher.requireEnd());    
      }     
   }
}

让我们编译并运行上面的程序，这将产生以下结果——

First Capturing Group, (a*b) Match String end():6
requireEnd():false
First Capturing Group, (a*b) Match String end():12
requireEnd():false
First Capturing Group, (a*b) Match String end():17
requireEnd():false