Java Longs.indexOf(long[] array, long[] target)用法及代码示例

Guava Longs Class的Longs.indexOf(long [] array，long [] target)方法接受两个参数array和target。如果目标存在于数组中，则该方法返回其首次出现的开始位置。如果目标在数组中不存在，则该方法返回-1。

用法:

public static int indexOf(long[] array, long[] target)

参数：该方法接受两个参数：

array:这是要在其中检查目标数组的索引的整数数组。
target:将要搜索的数组作为指定数组的sub-sequence。

返回值：该方法返回一个整数值，如下所示：

如果目标数组中存在目标数组，它将返回目标第一次出现的起始位置。
否则，如果目标在数组中不存在，则返回-1。

异常：该方法不会引发任何异常。

以下示例说明了上述方法的实现：

范例1：

// Java code to show implementation of 
// Guava's Longs.indexOf(long[] array, 
// long[] target) method 
  
import com.google.common.primitives.Longs; 
import java.util.Arrays; 
  
class GFG { 
  
    // Driver's code 
    public static void main(String[] args) 
    { 
  
        // Creating an long array 
        long[] arr = { 1, 2, 3, 4, 3, 5 }; 
  
        long[] target = { 3, 4, 3 }; 
  
        System.out.println("Array:"
                           + Arrays.toString(arr)); 
  
        System.out.println("Target Array:"
                           + Arrays.toString(target)); 
  
        // Using Longs.indexOf(long[] array, long[] target) 
        // method to get the start position of the first 
        // occurrence of the specified target within array, 
        // or -1 if there is no such occurrence. 
        int index = Longs.indexOf(arr, target); 
  
        if (index != -1) { 
            System.out.println("Target is present at index "
                               + index); 
        } 
        else { 
            System.out.println("Target is not present "
                               + "in the array"); 
        } 
    } 
}

输出：

Array:[1, 2, 3, 4, 3, 5]
Target Array:[3, 4, 3]
Target is present at index 2

范例2：

// Java code to show implementation of 
// Guava's Longs.indexOf(long[] array, 
// long[] target) method 
  
import com.google.common.primitives.Longs; 
import java.util.Arrays; 
  
class GFG { 
  
    // Driver's code 
    public static void main(String[] args) 
    { 
  
        // Creating an long array 
        long[] arr = { 3, 5, 7, 11, 13 }; 
  
        long[] target = { 23, 37 }; 
  
        System.out.println("Array:"
                           + Arrays.toString(arr)); 
  
        System.out.println("Target Array:"
                           + Arrays.toString(target)); 
  
        // Using Longs.indexOf(long[] array, long[] target) 
        // method to get the start position of the first 
        // occurrence of the specified target within array, 
        // or -1 if there is no such occurrence. 
        int index = Longs.indexOf(arr, target); 
  
        if (index != -1) { 
            System.out.println("Target is present at index "
                               + index); 
        } 
        else { 
            System.out.println("Target is not present"
                               + " in the array"); 
        } 
    } 
}

输出：

Array:[3, 5, 7, 11, 13]
Target Array:[23, 37]
Target is not present in the array

参考： https://google.github.io/guava/releases/21.0/api/docs/com/google/common/primitives/Longs.html#indexOf-long:A-long:A-

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注：本文由纯净天空筛选整理自Sahil_Bansall大神的英文原创作品 Java Guava | Longs.indexOf(long[] array, long[] target) method with Examples。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。