C库函数isgraph()检查字符是否为图形字符。已知具有图形表示的字符为图形字符。例如：‘:’‘;’‘?’‘@’等。
句法 -
#include <ctype.h> int isgraph(int ch);
返回值 -如果 ch 是空格以外的任何可打印字符，则函数返回非零值，否则返回 0。
对于 ASCII 环境，可打印字符在 0X21 到 0X7E 的范围内。
代码 -
// code to check graphical character
#include <stdio.h>
#include <ctype.h>
int main()
{
char var1 = 'g';
char var2 = ' ';
char var3 = '1';
if (isgraph(var1))
printf("var1 = |%c| can be printed\n", var1);
else
printf("var1 = |%c| can't be printed\n", var1);
if (isgraph(var2))
printf("var2 = |%c| can be printed\n", var2);
else
printf("var2 = |%c| can't be printed\n", var2);
if (isgraph(var3))
printf("var3 = |%c| can be printed\n", var3);
else
printf("var3 = |%c| can't be printed\n", var3);
return (0);
}输出-
var1 = |g| can be printed var2 = | | can't be printed var3 = |1| can be printed
代码 -
// code to print all Graphical Characters
#include <stdio.h>
#include <ctype.h>
int main()
{
int i;
printf("In C programming All graphic "
"characters are:\n");
for (i = 0; i <= 127; ++i)
if (isgraph(i) != 0)
printf("%c ", i);
return 0;
}输出-
In C programming All graphic characters are:
! " # $ % & ' ( ) * +, - . / 0 1 2 3 4 5 6 7 8 9
:; ? @ A B C D E F G H I J K L M N O P Q R S T U
V W X Y Z [ \ ] ^ _ ` a b c d e f g h i j k l m n
o p q r s t u v w x y z { | } ~
相关用法
注：本文由纯净天空筛选整理自GeeksforGeeks大神的英文原创作品 isgraph() C library function。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。