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Java Integer toString()用法及代码示例


  1. java.lang.Integer.toString()是Java中的内置方法,用于返回表示此Integer值的String对象。

    用法:

    public static String toString()

    参数:该方法不接受任何参数。

    返回值:该方法返回特定Integer值的字符串对象。


    以下示例程序旨在说明Java.lang.Integer.toString()方法:

    // Java program to illustrate the 
    // toString() Method 
    import java.lang.*; 
      
    public class Geeks{ 
      
    public static void main(String[] args) { 
      
        Integer obj = new Integer(8); 
          
        //It will return a string representation      
        String stringvalue1 = obj.toString(); 
        System.out.println("String Value= " +  
                                stringvalue1); 
          
          
            Integer obj3 = new Integer(10); 
          
        //It will return a string representation  
        String stringvalue3 = obj3.toString(); 
        System.out.println("String Value = " +  
                                stringvalue3); 
          
    } 
    }
    输出:
    String Value= 8
    String Value = 10
    
  2. java.lang.Integer.toString(int a)是Java中的内置方法,用于返回String对象,该String对象表示参数中指定的整数。
    用法:
    public static String toString(int a)

    参数:该方法接受一个整数类型的参数a,表示需要转换为字符串的整数。

    返回值:该方法以特定基数返回参数的字符串表示形式。

    例子:

    For base 8: 
    Input: int a = 75 
    Output: "75"
    
    For base 10:
    Input: int a = -787 
    Output: "-787"
    

    以下示例程序旨在说明Java.lang.Integer.toString(int a)方法:
    示例1:

    // Java program to illustrate the 
    // toString(int a) method 
    import java.lang.*; 
      
    public class Geeks{ 
      
    public static void main(String[] args) { 
      
        Integer obj = new Integer(8); 
          
        // It will return a string representation 
            // in base 8 
        String stringvalue1 = obj.toString(75); 
        System.out.println("String Value = " +  
                                stringvalue1); 
          
        Integer obj2 = new Integer(8); 
          
        // It will return a string representation 
            // in base 2 
        String stringvalue2 = obj2.toString(6787); 
        System.out.println("String Value = " +  
                                stringvalue2); 
          
          
            Integer obj3 = new Integer(10); 
          
        // It will return a string representation  
            // in base 10 
        String stringvalue3 = obj3.toString(-787); 
        System.out.println("String Value = " +  
                                stringvalue3); 
          
    } 
    } 
    输出:
    String Value = 75
    String Value = 6787
    String Value = -787
    

    示例2:用于十进制和字符串参数。
    注意:这会导致错误,并且还会导致缺少合适的Integer构造函数。

    // Java program to illustrate the 
    // Java.lang.Integer.toString(int a)method 
    import java.lang.*; 
    public class Geeks{ 
      
    public static void main(String[] args) { 
        Integer obj = new Integer(8);     
        String stringvalue1 = obj.toString(58.5); 
        System.out.println("String Value = " +  
                                stringvalue1); 
          
        Integer obj2 = new Integer(8);     
        String stringvalue2 = obj2.toString("317"); 
        System.out.println("String Value = " +  
                                stringvalue2); 
          
          
        // Empty constructor will result in an error 
        Integer obj3 = new Integer(); 
        String stringvalue3 = obj3.toString(-787); 
        System.out.println("String Value = " +  
                                stringvalue3); 
          
    } 
    } 

    输出:


    prog.java:8: error: incompatible types: possible 
    lossy conversion from double to int
        String stringvalue1 = obj.toString(58.5);
                                           ^
    prog.java:12: error: incompatible types: String cannot 
    be converted to int
        String stringvalue2 = obj2.toString("317");
                                            ^
    prog.java:17: error: no suitable constructor found for 
    Integer(no arguments)
        Integer obj3 = new Integer();
                       ^
        constructor Integer.Integer(int) is not applicable
          (actual and formal argument lists differ in length)
        constructor Integer.Integer(String) is not applicable
          (actual and formal argument lists differ in length)
    Note: Some messages have been simplified; recompile with 
    -Xdiags:verbose to get full output
    3 errors
  3. java.lang.Integer.toString(int a,int base)是Java中的一个内置方法,用于返回第二个参数base指定的base中参数a的字符串表示形式。如果基数/基数小于Character.MIN_RADIX或大于Character.MAX_RADIX,则使用基数10。用作数字的ASCII字符:0到9和a到z。
    用法:
    public static String toString(int a, int base)

    参数:该方法接受两个参数:

    • a:这是整数类型,是指要转换的整数值。
    • base:这也是整数类型,是表示字符串时要使用的基数。

    返回值:该方法以指定的基数返回指定参数的字符串表示形式。

    例子:

    Input: a = 71, base = 2
    Output: 1000111
    
    Input: a = 314, base = 16
    Output: 13a
    

    以下示例程序旨在说明Java.lang.Integer.toString(int a,int base)方法:
    示例1:

    // Java program to illustrate the 
    // toString(int, int) Method 
    import java.lang.*; 
      
    public class Geeks{ 
      
    public static void main(String[] args) { 
      
            Integer a = new Integer(10); 
          
        // It returns a string representation  
            // in base 2 
        String returnvalue = a.toString(5254, 2); 
        System.out.println("String Value = " +  
                                returnvalue); 
      
        // It returns a string representation  
            // in base 8 
        returnvalue = a.toString(35, 8); 
        System.out.println("String Value = " +  
                                returnvalue); 
      
        // It returns a string representation  
            // in base 16 
        returnvalue = a.toString(47, 16); 
        System.out.println("String Value = " +  
                                returnvalue); 
      
        // It returns a string representation  
            // in base 10 
        returnvalue = a.toString(451, 10); 
        System.out.println("String Value = " +  
                                returnvalue); 
    } 
    } 
    输出:
    String Value = 1010010000110
    String Value = 43
    String Value = 2f
    String Value = 451
    

    示例2:

    // Java program to illustrate the 
    // toString(int, int) Method 
    import java.lang.*; 
      
    public class Geeks{ 
      
    public static void main(String[] args) { 
      
            Integer a = new Integer(10); 
          
        // It returns a string representation  
            // in base 2 
        String returnvalue = a.toString(-525, 2); 
        System.out.println("String Value = " +  
                                returnvalue); 
      
        // It returns a string representation  
            // in base 8 
        returnvalue = a.toString(31, 8); 
        System.out.println("String Value = " +  
                                returnvalue); 
      
        // It returns a string representation  
            // in base 16 
        returnvalue = a.toString(28, 16); 
        System.out.println("String Value = " +  
                                returnvalue); 
      
        // It returns a string representation  
            // in base 10 
        returnvalue = a.toString(29, 10); 
        System.out.println("String Value = " +  
                                returnvalue); 
    } 
    } 
    输出:
    String Value = -1000001101
    String Value = 37
    String Value = 1c
    String Value = 29
    


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注:本文由纯净天空筛选整理自ankita_chowrasia大神的英文原创作品 Integer toString() in Java。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。