- java.lang.Integer.toString()是Java中的内置方法,用于返回表示此Integer值的String对象。
用法:
public static String toString()
参数:该方法不接受任何参数。
返回值:该方法返回特定Integer值的字符串对象。
以下示例程序旨在说明Java.lang.Integer.toString()方法:
// Java program to illustrate the // toString() Method import java.lang.*; public class Geeks{ public static void main(String[] args) { Integer obj = new Integer(8); //It will return a string representation String stringvalue1 = obj.toString(); System.out.println("String Value= " + stringvalue1); Integer obj3 = new Integer(10); //It will return a string representation String stringvalue3 = obj3.toString(); System.out.println("String Value = " + stringvalue3); } }
输出:String Value= 8 String Value = 10
- java.lang.Integer.toString(int a)是Java中的内置方法,用于返回String对象,该String对象表示参数中指定的整数。
用法:public static String toString(int a)
参数:该方法接受一个整数类型的参数a,表示需要转换为字符串的整数。
返回值:该方法以特定基数返回参数的字符串表示形式。
例子:
For base 8: Input: int a = 75 Output: "75" For base 10: Input: int a = -787 Output: "-787"
以下示例程序旨在说明Java.lang.Integer.toString(int a)方法:
示例1:// Java program to illustrate the // toString(int a) method import java.lang.*; public class Geeks{ public static void main(String[] args) { Integer obj = new Integer(8); // It will return a string representation // in base 8 String stringvalue1 = obj.toString(75); System.out.println("String Value = " + stringvalue1); Integer obj2 = new Integer(8); // It will return a string representation // in base 2 String stringvalue2 = obj2.toString(6787); System.out.println("String Value = " + stringvalue2); Integer obj3 = new Integer(10); // It will return a string representation // in base 10 String stringvalue3 = obj3.toString(-787); System.out.println("String Value = " + stringvalue3); } }
输出:String Value = 75 String Value = 6787 String Value = -787
示例2:用于十进制和字符串参数。
注意:这会导致错误,并且还会导致缺少合适的Integer构造函数。// Java program to illustrate the // Java.lang.Integer.toString(int a)method import java.lang.*; public class Geeks{ public static void main(String[] args) { Integer obj = new Integer(8); String stringvalue1 = obj.toString(58.5); System.out.println("String Value = " + stringvalue1); Integer obj2 = new Integer(8); String stringvalue2 = obj2.toString("317"); System.out.println("String Value = " + stringvalue2); // Empty constructor will result in an error Integer obj3 = new Integer(); String stringvalue3 = obj3.toString(-787); System.out.println("String Value = " + stringvalue3); } }
输出:
prog.java:8: error: incompatible types: possible lossy conversion from double to int String stringvalue1 = obj.toString(58.5); ^ prog.java:12: error: incompatible types: String cannot be converted to int String stringvalue2 = obj2.toString("317"); ^ prog.java:17: error: no suitable constructor found for Integer(no arguments) Integer obj3 = new Integer(); ^ constructor Integer.Integer(int) is not applicable (actual and formal argument lists differ in length) constructor Integer.Integer(String) is not applicable (actual and formal argument lists differ in length) Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output 3 errors
- java.lang.Integer.toString(int a,int base)是Java中的一个内置方法,用于返回第二个参数base指定的base中参数a的字符串表示形式。如果基数/基数小于Character.MIN_RADIX或大于Character.MAX_RADIX,则使用基数10。用作数字的ASCII字符:0到9和a到z。
用法:public static String toString(int a, int base)
参数:该方法接受两个参数:
- a:这是整数类型,是指要转换的整数值。
- base:这也是整数类型,是表示字符串时要使用的基数。
返回值:该方法以指定的基数返回指定参数的字符串表示形式。
例子:
Input: a = 71, base = 2 Output: 1000111 Input: a = 314, base = 16 Output: 13a
以下示例程序旨在说明Java.lang.Integer.toString(int a,int base)方法:
示例1:// Java program to illustrate the // toString(int, int) Method import java.lang.*; public class Geeks{ public static void main(String[] args) { Integer a = new Integer(10); // It returns a string representation // in base 2 String returnvalue = a.toString(5254, 2); System.out.println("String Value = " + returnvalue); // It returns a string representation // in base 8 returnvalue = a.toString(35, 8); System.out.println("String Value = " + returnvalue); // It returns a string representation // in base 16 returnvalue = a.toString(47, 16); System.out.println("String Value = " + returnvalue); // It returns a string representation // in base 10 returnvalue = a.toString(451, 10); System.out.println("String Value = " + returnvalue); } }
输出:String Value = 1010010000110 String Value = 43 String Value = 2f String Value = 451
示例2:
// Java program to illustrate the // toString(int, int) Method import java.lang.*; public class Geeks{ public static void main(String[] args) { Integer a = new Integer(10); // It returns a string representation // in base 2 String returnvalue = a.toString(-525, 2); System.out.println("String Value = " + returnvalue); // It returns a string representation // in base 8 returnvalue = a.toString(31, 8); System.out.println("String Value = " + returnvalue); // It returns a string representation // in base 16 returnvalue = a.toString(28, 16); System.out.println("String Value = " + returnvalue); // It returns a string representation // in base 10 returnvalue = a.toString(29, 10); System.out.println("String Value = " + returnvalue); } }
输出:String Value = -1000001101 String Value = 37 String Value = 1c String Value = 29
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注:本文由纯净天空筛选整理自ankita_chowrasia大神的英文原创作品 Integer toString() in Java。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。