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GO Sub32用法及代码示例

GO语言"math/bits"包中"Sub32"函数的用法及代码示例。

用法:

func Sub32(x, y, borrow uint32)(diff, borrowOut uint32)

Sub32 返回 x、y 和借位的差,diff = x - y - 借位。借位输入必须为 0 或 1;否则行为未定义。 borrowOut 输出保证为 0 或 1。

此函数的执行时间不依赖于输入。

例子:

package main

import (
    "fmt"
    "math/bits"
)

func main() {
    // First number is 33<<32 + 23
    n1 := []uint32{33, 23}
    // Second number is 21<<32 + 12
    n2 := []uint32{21, 12}
    // Sub them together without producing carry.
    d1, carry := bits.Sub32(n1[1], n2[1], 0)
    d0, _ := bits.Sub32(n1[0], n2[0], carry)
    nsum := []uint32{d0, d1}
    fmt.Printf("%v - %v = %v (carry bit was %v)\n", n1, n2, nsum, carry)

    // First number is 3<<32 + 2147483647
    n1 = []uint32{3, 0x7fffffff}
    // Second number is 1<<32 + 2147483648
    n2 = []uint32{1, 0x80000000}
    // Sub them together producing carry.
    d1, carry = bits.Sub32(n1[1], n2[1], 0)
    d0, _ = bits.Sub32(n1[0], n2[0], carry)
    nsum = []uint32{d0, d1}
    fmt.Printf("%v - %v = %v (carry bit was %v)\n", n1, n2, nsum, carry)
}

输出:

[33 23] - [21 12] = [12 11] (carry bit was 0)
[3 2147483647] - [1 2147483648] = [1 4294967295] (carry bit was 1)

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注:本文由纯净天空筛选整理自golang.google.cn大神的英文原创作品 Sub32。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。