Java Duration withSeconds(long)用法及代码示例

java.time包中的Duration Class的withSeconds(long)方法用于获取此持续时间的不可变副本，并将指定的秒数作为参数传递。

用法:

public Duration withSeconds(long amountOfSeconds)

参数：此方法接受参数amountOfSeconds，即秒数。

返回值：此方法返回作为参数传递的秒数的持续时间。

以下示例说明了Duration.withSeconds()方法：

示例1:

// Java code to illustrate withSeconds() method 
  
import java.time.Duration; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
  
        // Get the amount of seconds 
        long amountOfSeconds = 300; 
  
        // Duration using parse() method 
        Duration duration 
            = Duration.parse("P2DT3H4M"); 
  
        // Get the duration in seconds 
        // using withSeconds() method 
        System.out.println(duration 
                               .withSeconds(amountOfSeconds)); 
    } 
}

输出：

PT5M

示例2:

// Java code to illustrate withSeconds() method 
  
import java.time.Duration; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
  
        // Get the amount of seconds 
        long amountOfSeconds = 3000; 
  
        // Duration using ofHours() method 
        Duration duration 
            = Duration.ofHours(5); 
  
        // Get the duration in seconds 
        // using withSeconds() method 
        System.out.println(duration 
                               .withSeconds(amountOfSeconds)); 
    } 
}

输出：

PT50M

参考： https://docs.oracle.com/javase/9/docs/api/java/time/Duration.html#withSeconds-long-

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注：本文由纯净天空筛选整理自Code_r大神的英文原创作品 Duration withSeconds(long) method in Java with Examples。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。