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C# Decimal.ToDouble()用法及代码示例


此方法用于将指定的Decimal的值转换为等效的双精度浮点数。此方法可能会产生舍入误差,因为双精度浮点数的有效位数比十进制数少。

用法: public static double ToDouble (decimal d);
Here, d is the decimal value which is to be converted.

返回值:它返回等于d的双精度浮点数。


例:

// C# program to demonstrate the 
// Decimal.ToDouble(Decimal) Method 
using System; 
  
class GFG { 
  
    // Main Method 
    public static void Main() 
    { 
        try { 
  
            // Taking decimal variables 
            Decimal dec1 = 0.0000000000134563456789M; 
            Decimal dec2 = 4589662514452860951234M; 
  
            // using ToDouble(Decimal) Method 
            Double val1 = Decimal.ToDouble(dec1); 
              
            // using ToDouble(Decimal) Method 
            Double val2 = Decimal.ToDouble(dec2); 
  
            // Printing the Double value 
            Console.WriteLine("The Double value "
                              + "is : {0}", val1); 
                                
            // Printing the Double value 
            Console.WriteLine("The Double value "
                              + "is : {0}", val2); 
                          
        } 
  
        catch (OverflowException e)  
        { 
            Console.Write("Exception Thrown: "); 
            Console.Write("{0}", e.GetType(), e.Message); 
        } 
    } 
}
输出:
The Double value is : 1.34563456789E-11
The Double value is : 4.58966251445286E+21

参考:



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注:本文由纯净天空筛选整理自Kirti_Mangal大神的英文原创作品 Decimal.ToDouble() Method in C#。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。