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Java ByteBuffer putInt()用法及代码示例


putInt(int value)

java.nio.ByteBuffer类的putInt(int value)方法用于按当前字节顺序将四个包含给定int值的字节按当前字节顺序写入此缓冲区的当前位置,然后将该位置增加4。

用法:

public abstract ByteBuffer putInt(int value)

参数:此方法将要写入的int值作为参数。


返回值:此方法返回此ByteBuffer。

异常:此方法引发以下异常:

  • BufferOverflowException-如果此缓冲区的当前位置不小于其限制
  • ReadOnlyBufferException-如果此缓冲区是只读的

以下示例说明了putInt(int value)方法:

范例1:

// Java program to demonstrate 
// putInt() method 
  
import java.nio.*; 
import java.util.*; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
  
        // Declaring the capacity of the ByteBuffer 
        int capacity = 12; 
  
        // Creating the ByteBuffer 
        try { 
  
            // creating object of ByteBuffer 
            // and allocating size capacity 
            ByteBuffer bb = ByteBuffer.allocate(capacity); 
  
            // putting the value in ByteBuffer 
            // using putInt() method 
            bb.putInt(23) 
                .putInt(24) 
                .putInt(30) 
                .rewind(); 
  
            // print the ByteBuffer 
            System.out.print("Original ByteBuffer:[ "); 
            for (int i = 1; i <= capacity / 4; i++) 
                System.out.print(bb.getInt() + " "); 
            System.out.print("]"); 
        } 
  
        catch (BufferOverflowException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
  
        catch (ReadOnlyBufferException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
    } 
}
输出:
Original ByteBuffer:[ 23 24 30 ]

范例2:演示BufferOverflowException。

// Java program to demonstrate 
// putInt() method 
  
import java.nio.*; 
import java.util.*; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
  
        // Declaring the capacity of the ByteBuffer 
        int capacity = 12; 
  
        // Creating the ByteBuffer 
        try { 
  
            // creating object of ByteBuffer 
            // and allocating size capacity 
            ByteBuffer bb = ByteBuffer.allocate(capacity); 
  
            // putting the value in ByteBuffer 
            // using putInt() method 
            bb.putInt(23) 
                .putInt(24) 
                .putInt(30) 
                .rewind(); 
  
            // print the ByteBuffer 
            System.out.print("Original ByteBuffer:[ "); 
            for (int i = 1; i <= capacity / 4; i++) 
                System.out.print(bb.getInt() + " "); 
            System.out.print("]"); 
  
            // putting the value in ByteBuffer 
            // using putInt() method 
            bb.putInt(234); 
        } 
  
        catch (BufferOverflowException e) { 
            System.out.println("\n\nbuffer's current position "
                               + "is not smaller than its limit"); 
            System.out.println("Exception throws:" + e); 
        } 
  
        catch (ReadOnlyBufferException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
    } 
}
输出:
Original ByteBuffer:[ 23 24 30 ]

buffer's current position is not smaller than its limit
Exception throws:java.nio.BufferOverflowException

范例3:演示ReadOnlyBufferException。

// Java program to demonstrate 
// putInt() method 
  
import java.nio.*; 
import java.util.*; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
  
        // Declaring the capacity of the ByteBuffer 
        int capacity = 12; 
  
        // Creating the ByteBuffer 
        try { 
  
            // creating object of ByteBuffer 
            // and allocating size capacity 
            ByteBuffer bb = ByteBuffer.allocate(capacity); 
  
            // putting the value in ByteBuffer 
            // using putInt() method 
            bb.putInt(23) 
                .putInt(24) 
                .putInt(30) 
                .rewind(); 
  
            // print the ByteBuffer 
            System.out.print("Original ByteBuffer:[ "); 
            for (int i = 1; i <= capacity / 4; i++) 
                System.out.print(bb.getInt() + " "); 
            System.out.print("]"); 
  
            // Creating a read-only copy of ByteBuffer 
            // using asReadOnlyBuffer() method 
            ByteBuffer bb1 = bb.asReadOnlyBuffer(); 
  
            System.out.println("\n\nTrying to put the int value"
                               + " in read-only buffer"); 
  
            // putting the value in readonly ByteBuffer 
            // using putInt() method 
            bb1.putInt(234); 
        } 
  
        catch (BufferOverflowException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
  
        catch (ReadOnlyBufferException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
    } 
}
输出:
Original ByteBuffer:[ 23 24 30 ]

Trying to put the int value in read only buffer
Exception throws:java.nio.ReadOnlyBufferException

putInt(int index, int value)

java.nio.ByteBuffer类的putInt(int index,int value)方法用于按给定索引将包含给定四个值(按当前字节顺序)的四个字节写入当前缓冲区。


用法:

public abstract ByteBuffer putInt(int index, int value)

参数:此方法将以下参数作为参数:

  • index:将写入字节的索引
  • value:要写入的int值

返回值:此方法返回此缓冲区。

异常:此方法引发以下异常:

  • IndexOutOfBoundsException-如果索引为负或不小于缓冲区的限制
  • ReadOnlyBufferException-如果此缓冲区是只读的

以下示例说明了putInt(int index,int value)方法:

范例1:

// Java program to demonstrate 
// putInt() method 
  
import java.nio.*; 
import java.util.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Declaring the capacity of the ByteBuffer 
        int capacity = 12; 
  
        // Creating the ByteBuffer 
        try { 
  
            // creating object of ByteBuffer 
            // and allocating size capacity 
            ByteBuffer bb = ByteBuffer.allocate(capacity); 
  
            // putting the value in ByteBuffer 
            // using putInt() at  index 0 
            bb.putInt(0, 23); 
  
            // putting the value in ByteBuffer 
            // using putInt() at  index 4 
            bb.putInt(4, 34); 
  
            // putting the value in ByteBuffer 
            // using putInt() at  index 8 
            bb.putInt(8, 27); 
  
            // rewinding the ByteBuffer 
            bb.rewind(); 
  
            // print the ByteBuffer 
            System.out.print("Original ByteBuffer:[ "); 
            for (int i = 1; i <= capacity / 4; i++) 
                System.out.print(bb.getInt() + "  "); 
            System.out.print("]\n"); 
        } 
  
        catch (IndexOutOfBoundsException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
  
        catch (ReadOnlyBufferException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
    } 
}
输出:
Original ByteBuffer:[ 23  34  27  ]

范例2:演示IndexOutOfBoundsException。

// Java program to demonstrate 
// putInt() method 
  
import java.nio.*; 
import java.util.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Declaring the capacity of the ByteBuffer 
        int capacity = 12; 
  
        // Creating the ByteBuffer 
        try { 
  
            // creating object of ByteBuffer 
            // and allocating size capacity 
            ByteBuffer bb = ByteBuffer.allocate(capacity); 
  
            // putting the value in ByteBuffer 
            // using putInt() at  index 0 
            bb.putInt(0, 23); 
  
            // putting the value in ByteBuffer 
            // using putInt() at  index 4 
            bb.putInt(4, 34); 
  
            // putting the value in ByteBuffer 
            // using putInt() at  index 8 
            bb.putInt(8, 27); 
  
            // rewinding the ByteBuffer 
            bb.rewind(); 
  
            // print the ByteBuffer 
            System.out.print("Original ByteBuffer:[ "); 
            for (int i = 1; i <= capacity / 4; i++) 
                System.out.print(bb.getInt() + "  "); 
            System.out.print("]\n"); 
  
            // putting the value in ByteBuffer 
            // using putInt() at  index -1 
            bb.putInt(-1, 45); 
        } 
  
        catch (IndexOutOfBoundsException e) { 
            System.out.println("\nindex is negative or not smaller "
                               + "than the buffer's limit"); 
            System.out.println("Exception throws:" + e); 
        } 
  
        catch (ReadOnlyBufferException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
    } 
}
输出:
Original ByteBuffer:[ 23  34  27  ]

index is negative or not smaller than the buffer's limit
Exception throws:java.lang.IndexOutOfBoundsException

范例3:演示ReadOnlyBufferException。

// Java program to demonstrate 
// putInt() method 
  
import java.nio.*; 
import java.util.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Declaring the capacity of the ByteBuffer 
        int capacity = 12; 
  
        // Creating the ByteBuffer 
        try { 
  
            // creating object of ByteBuffer 
            // and allocating size capacity 
            ByteBuffer bb = ByteBuffer.allocate(capacity); 
  
            // Creating a read-only copy of ByteBuffer 
            // using asReadOnlyBuffer() method 
            ByteBuffer bb1 = bb.asReadOnlyBuffer(); 
  
            System.out.println("Trying to put the int value"
                               + " in read-only buffer"); 
  
            // putting the value in readonly ByteBuffer 
            // using putInt() method 
            bb1.putInt(0, 23); 
        } 
  
        catch (IndexOutOfBoundsException e) { 
            System.out.println("\nindex is negative or not smaller "
                               + "than the buffer's limit"); 
            System.out.println("Exception throws:" + e); 
        } 
  
        catch (ReadOnlyBufferException e) { 
  
            System.out.println("Exception throws:" + e); 
        } 
    } 
}
输出:
Trying to put the int value in read only buffer
Exception throws:java.nio.ReadOnlyBufferException

参考:



相关用法


注:本文由纯净天空筛选整理自RohitPrasad3大神的英文原创作品 ByteBuffer putInt() methods in Java with Examples。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。