Java AbstractSet retainAll()用法及代码示例

java.util.AbstractSet类的retainAll()方法用于从该集合中保留指定集合中包含的所有元素。

用法:

public boolean retainAll(Collection c)

参数：此方法将集合c作为包含要从该集合保留的元素的参数。

返回值：如果此集合因调用而更改，则此方法返回true。

异常：如果此集合包含null元素并且指定的集合不允许null元素(可选)，或者如果指定的collection为null，则此方法引发NullPointerException。

以下示例说明了retainAll()方法。

示例1:

// Java program to demonstrate 
// retainAll() method for Integer value 
  
import java.util.*; 
  
public class GFG1 { 
    public static void main(String[] argv) throws Exception 
    { 
  
        try { 
  
            // Creating object of AbstractSet<Integer> 
            AbstractSet<Integer> 
                arrset1 = new TreeSet<Integer>(); 
  
            // Populating arrset1 
            arrset1.add(1); 
            arrset1.add(2); 
            arrset1.add(3); 
            arrset1.add(4); 
            arrset1.add(5); 
  
            // print arrset1 
            System.out.println("AbstractSet before "
                               + "retainAll() operation : "
                               + arrset1); 
  
            // Creating another object of  AbstractSet<Integer> 
            AbstractSet<Integer> 
                arrset2 = new TreeSet<Integer>(); 
            arrset2.add(1); 
            arrset2.add(2); 
            arrset2.add(3); 
  
            // print arrset2 
            System.out.println("Collection Elements"
                               + " to be retained : "
                               + arrset2); 
  
            // Removing elements from arrset 
            // specified in arrset2 
            // using retainAll() method 
            arrset1.retainAll(arrset2); 
  
            // print arrset1 
            System.out.println("AbstractSet after "
                               + "retainAll() operation : "
                               + arrset1); 
        } 
  
        catch (NullPointerException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}

输出：

AbstractSet before retainAll() operation : [1, 2, 3, 4, 5]
Collection Elements to be retained : [1, 2, 3]
AbstractSet after retainAll() operation : [1, 2, 3]

示例2:对于NullPointerException

// Java program to demonstrate 
// retainAll() method for Integer value 
  
import java.util.*; 
  
public class GFG1 { 
    public static void main(String[] argv) throws Exception 
    { 
  
        try { 
  
            // Creating object of AbstractSet<Integer> 
            AbstractSet<Integer> 
                arrset1 = new TreeSet<Integer>(); 
  
            // Populating arrset1 
            arrset1.add(1); 
            arrset1.add(2); 
            arrset1.add(3); 
            arrset1.add(4); 
            arrset1.add(5); 
  
            // print arrset1 
            System.out.println("AbstractSet before "
                               + "retainAll() operation : "
                               + arrset1); 
  
            // Creating another object of  AbstractSet<Integer> 
            AbstractSet<Integer> 
                arrset2 = null; 
  
            // print arrset2 
            System.out.println("Collection Elements"
                               + " to be retained : "
                               + arrset2); 
  
            System.out.println("\nTrying to pass "
                               + "null as a specified element\n"); 
  
            // Removing elements from arrset 
            // specified in arrset2 
            // using retainAll() method 
            arrset1.retainAll(arrset2); 
  
            // print arrset1 
            System.out.println("AbstractSet after "
                               + "retainAll() operation : "
                               + arrset1); 
        } 
  
        catch (NullPointerException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}

输出：

AbstractSet before retainAll() operation : [1, 2, 3, 4, 5]
Collection Elements to be retained : null

Trying to pass null as a specified element

Exception thrown : java.lang.NullPointerException

相关用法

注：本文由纯净天空筛选整理自Code_r大神的英文原创作品 AbstractSet retainAll() method in Java with Example。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。