Java AbstractList get()用法及代码示例

java.util.AbstractList 类的 get() 方法用于返回此列表中指定位置的元素。

用法:

public abstract E get(int index)

参数：该方法将元素的索引作为参数，即要返回的元素。

Returns Value:此方法返回此列表中指定位置的元素。

异常：如果索引超出范围(索引 = size())，此方法将引发 IndexOutOfBoundsException。

以下是说明 get() 方法的示例。

范例1：


// Java program to demonstrate
// get() method
// for Integer value
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv)
        throws Exception
    {
  
        try {
  
            // Creating object of AbstractList<Integer>
            AbstractList<Integer>
                arrlist1 = new ArrayList<Integer>();
  
            // Populating arrlist1
            arrlist1.add(10);
            arrlist1.add(20);
            arrlist1.add(30);
            arrlist1.add(40);
            arrlist1.add(50);
  
            // print arrlist1
            System.out.println("ArrayListlist:"
                               + arrlist1);
  
            // getting the value at the index 3
            // using get() method
            int value = arrlist1.get(3);
  
            // print the value
            System.out.println("Element at index 3:"
                               + value);
        }
  
        catch (IndexOutOfBoundsException e) {
            System.out.println("Exception thrown:" + e);
        }
    }
}

输出：

ArrayListlist:[10, 20, 30, 40, 50]
Element at index 3:40

范例2：


// Java program to demonstrate
// get() method
// for IndexOutOfBoundsException
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv)
        throws Exception
    {
        try {
  
            // Creating object of AbstractList<Integer>
            AbstractList<Integer>
                arrlist1 = new ArrayList<Integer>();
  
            // Populating arrlist1
            arrlist1.add(10);
            arrlist1.add(20);
            arrlist1.add(30);
            arrlist1.add(40);
            arrlist1.add(50);
  
            // print arrlist1
            System.out.println("ArrayListlist:"
                               + arrlist1);
  
            // getting the value at the index 7
            // using get() method
            System.out.println("\nTrying to get "
                               + "the element from out"
                               + " of range index ");
            int value = arrlist1.get(7);
  
            // print the value
            System.out.println("Element at index 7:"
                               + value);
        }
  
        catch (IndexOutOfBoundsException e) {
            System.out.println("Exception thrown:" + e);
        }
    }
}

输出：

ArrayListlist:[10, 20, 30, 40, 50]

Trying to get the element from out of range index 
Exception thrown:java.lang.IndexOutOfBoundsException:Index:7, Size:5

相关用法

注：本文由纯净天空筛选整理自RohitPrasad3大神的英文原创作品 AbstractList get() method in Java with Examples。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。