本文整理汇总了VB.NET中System.Reflection.AmbiguousMatchException.AmbiguousMatchException构造函数的典型用法代码示例。如果您正苦于以下问题：VB.NET AmbiguousMatchException构造函数的具体用法？VB.NET AmbiguousMatchException怎么用？VB.NET AmbiguousMatchException使用的例子？那么恭喜您, 这里精选的构造函数代码示例或许可以为您提供帮助。
在下文中一共展示了AmbiguousMatchException构造函数的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的VB.NET代码示例。
示例1: Mymethod
' 导入命名空间
Imports System.Reflection
Namespace Ambiguity
Class Myambiguous
'The first overload is typed to an Int32
Overloads Public Shared Sub Mymethod(number As Int32)
Console.WriteLine("I am from 'Int32' method")
End Sub
'The second overload is typed to a string
Overloads Public Shared Sub Mymethod(alpha As String)
Console.WriteLine("I am from 'string' method.")
End Sub
Public Shared Sub Main()
Try
'The following does not cause as exception
Mymethod(2) ' goes to Mymethod Int32)
Mymethod("3") ' goes to Mymethod(string)
Dim Mytype As Type = Type.GetType("Ambiguity.Myambiguous")
Dim Mymethodinfo32 As MethodInfo = Mytype.GetMethod("Mymethod", New Type() {GetType(Int32)})
Dim Mymethodinfostr As MethodInfo = Mytype.GetMethod("Mymethod", New Type() {GetType(System.String)})
'Invoke a method, utilizing a Int32 integer
Mymethodinfo32.Invoke(Nothing, New Object() {2})
'Invoke the method utilizing a string
Mymethodinfostr.Invoke(Nothing, New Object() {"1"})
'The following line causes an ambiguious exception
Dim Mymethodinfo As MethodInfo = Mytype.GetMethod("Mymethod")
' end of try block
Catch ex As AmbiguousMatchException
Console.WriteLine(vbNewLine + "{0}" + vbNewLine + "{1}", ex.GetType().FullName, ex.Message)
Catch
Console.WriteLine(vbNewLine + "Some other exception.")
End Try
Return
End Sub
End Class
End Namespace输出：
I am from 'Int32' method I am from 'string' method. I am from 'Int32' method I am from 'string' method. System.Reflection.AmbiguousMatchException Ambiguous match found.