本文整理汇总了VB.NET中System.Exception.Exception构造函数的典型用法代码示例。如果您正苦于以下问题:VB.NET Exception构造函数的具体用法?VB.NET Exception怎么用?VB.NET Exception使用的例子?那么, 这里精选的构造函数代码示例或许可以为您提供帮助。您也可以进一步了解该构造函数所在类System.Exception
的用法示例。
在下文中一共展示了Exception构造函数的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的VB.NET代码示例。
示例1: New
' Example for the Exception( ) constructor.
Namespace NDP_UE_VB
' Derive an exception with a predefined message.
Class NotEvenException
Inherits Exception
Public Sub New( )
MyBase.New( _
"The argument to a function requiring " & _
"even input is not divisible by 2." )
End Sub
End Class
Module NewExceptionDemo
Sub Main( )
Console.WriteLine( _
"This example of the Exception( ) constructor " & _
"generates the following output." )
Console.WriteLine( vbCrLf & _
"Here, an exception is thrown using the " & vbCrLf & _
"parameterless constructor of the base class." & _
vbCrLf )
CalcHalf( 12 )
CalcHalf( 15 )
Console.WriteLine(vbCrLf & _
"Here, an exception is thrown using the " & vbCrLf & _
"parameterless constructor of a derived class." & _
vbCrLf )
CalcHalf2( 24 )
CalcHalf2( 27 )
End Sub
' Half throws a base exception if the input is not even.
Function Half( input As Integer ) As Integer
If input Mod 2 <> 0 Then
Throw New Exception( )
Else
Return input / 2
End If
End Function ' Half
' Half2 throws a derived exception if the input is not even.
Function Half2( input As Integer ) As Integer
If input Mod 2 <> 0 Then
Throw New NotEvenException( )
Else
Return input / 2
End If
End Function ' Half2
' CalcHalf calls Half and catches any thrown exceptions.
Sub CalcHalf( input As Integer )
Try
Dim halfInput As Integer = Half( input )
Console.WriteLine( _
"Half of {0} is {1}.", input, halfInput )
Catch ex As Exception
Console.WriteLine( ex.ToString( ) )
End Try
End Sub
' CalcHalf2 calls Half2 and catches any thrown exceptions.
Sub CalcHalf2( input As Integer )
Try
Dim halfInput As Integer = Half2( input )
Console.WriteLine( _
"Half of {0} is {1}.", input, halfInput )
Catch ex As Exception
Console.WriteLine( ex.ToString( ) )
End Try
End Sub
End Module ' NewExceptionDemo
End Namespace ' NDP_UE_VB
输出:
Here, an exception is thrown using the parameterless constructor of the base class. Half of 12 is 6. System.Exception: Exception of type System.Exception was thrown. at NDP_UE_VB.NewExceptionDemo.Half(Int32 input) at NDP_UE_VB.NewExceptionDemo.CalcHalf(Int32 input) Here, an exception is thrown using the parameterless constructor of a derived class. Half of 24 is 12. NDP_UE_VB.NotEvenException: The argument to a function requiring even input i s not divisible by 2. at NDP_UE_VB.NewExceptionDemo.Half2(Int32 input) at NDP_UE_VB.NewExceptionDemo.CalcHalf2(Int32 input)
示例2: New
' Example for the Exception( String ) constructor( String ).
Namespace NDP_UE_VB
' Derive an exception with a specifiable message.
Class NotEvenException
Inherits Exception
Private Const notEvenMessage As String = _
"The argument to a function requiring " & _
"even input is not divisible by 2."
Public Sub New()
MyBase.New(notEvenMessage)
End Sub
Public Sub New(auxMessage As String)
MyBase.New(String.Format("{0} - {1}", _
auxMessage, notEvenMessage))
End Sub
End Class
Module NewSExceptionDemo
Sub Main()
Console.WriteLine( _
"This example of the Exception( String )" & vbCrLf & _
"constructor generates the following output." )
Console.WriteLine( vbCrLf & _
"Here, an exception is thrown using the " & vbCrLf & _
"constructor of the base class." & vbCrLf )
CalcHalf(18)
CalcHalf(21)
Console.WriteLine(vbCrLf & _
"Here, an exception is thrown using the " & vbCrLf & _
"constructor of a derived class." & vbCrLf )
CalcHalf2(30)
CalcHalf2(33)
End Sub
' Half throws a base exception if the input is not even.
Function Half(input As Integer) As Integer
If input Mod 2 <> 0 Then
Throw New Exception( String.Format( _
"The argument {0} is not divisible by 2.", _
input ) )
Else
Return input / 2
End If
End Function ' Half
' Half2 throws a derived exception if the input is not even.
Function Half2(input As Integer) As Integer
If input Mod 2 <> 0 Then
Throw New NotEvenException( _
String.Format( "Invalid argument: {0}", input ) )
Else
Return input / 2
End If
End Function ' Half2
' CalcHalf calls Half and catches any thrown exceptions.
Sub CalcHalf(input As Integer)
Try
Dim halfInput As Integer = Half(input)
Console.WriteLine( _
"Half of {0} is {1}.", input, halfInput )
Catch ex As Exception
Console.WriteLine( ex.ToString( ) )
End Try
End Sub
' CalcHalf2 calls Half2 and catches any thrown exceptions.
Sub CalcHalf2( input As Integer )
Try
Dim halfInput As Integer = Half2( input )
Console.WriteLine( _
"Half of {0} is {1}.", input, halfInput )
Catch ex As Exception
Console.WriteLine( ex.ToString( ) )
End Try
End Sub
End Module ' NewSExceptionDemo
End Namespace ' NDP_UE_VB
' This example of the Exception( String )
输出:
Here, an exception is thrown using the constructor of the base class. Half of 18 is 9. System.Exception: The argument 21 is not divisible by 2. at NDP_UE_VB.NewSExceptionDemo.Half(Int32 input) at NDP_UE_VB.NewSExceptionDemo.CalcHalf(Int32 input) Here, an exception is thrown using the constructor of a derived class. Half of 30 is 15. NDP_UE_VB.NotEvenException: Invalid argument: 33 - The argument to a function requiring even input is not divisible by 2. at NDP_UE_VB.NewSExceptionDemo.Half2(Int32 input) at NDP_UE_VB.NewSExceptionDemo.CalcHalf2(Int32 input)
示例3: New
' If compiling with the Visual Basic compiler (vbc.exe) from the command
' prompt, be sure to add the following switch:
' /reference:System.Runtime.Serialization.Formatters.Soap.dll
Imports System.IO
Imports System.Runtime.Serialization
Imports System.Runtime.Serialization.Formatters.Soap
Imports System.Security.Permissions
' Define a serializable derived exception class.
<Serializable()> _
Class SecondLevelException
Inherits Exception
' This public constructor is used by class instantiators.
Public Sub New( message As String, inner As Exception )
MyBase.New( message, inner )
HelpLink = "http://MSDN.Microsoft.com"
Source = "Exception_Class_Samples"
End Sub
' This protected constructor is used for deserialization.
Protected Sub New( info As SerializationInfo, _
context As StreamingContext )
MyBase.New( info, context )
End Sub
' GetObjectData performs a custom serialization.
<SecurityPermissionAttribute(SecurityAction.Demand, _
SerializationFormatter:=True)> _
Overrides Sub GetObjectData( info As SerializationInfo, _
context As StreamingContext)
' Change the case of two properties, and then use the
' method of the base class.
HelpLink = HelpLink.ToLower()
Source = Source.ToUpperInvariant()
MyBase.GetObjectData(info, context)
End Sub
End Class
Module SerializationDemo
Sub Main()
Console.WriteLine( _
"This example of the Exception constructor " & _
"and Exception.GetObjectData " & vbCrLf & _
"with SerializationInfo and StreamingContext " & _
"parameters generates " & vbCrLf & _
"the following output." & vbCrLf )
' This code forces a division by 0 and catches the
' resulting exception.
Try
Try
Dim zero As Integer = 0
Dim ecks As Integer = 1 \ zero
' Create a new exception to throw again.
Catch ex As Exception
Dim newExcept As New SecondLevelException( _
"Forced a division by 0 and threw " & _
"another exception.", ex )
Console.WriteLine( _
"Forced a division by 0, caught the " & _
"resulting exception, " & vbCrLf & _
"and created a derived exception:" & vbCrLf )
Console.WriteLine( "HelpLink: {0}", _
newExcept.HelpLink )
Console.WriteLine( "Source: {0}", _
newExcept.Source )
' This FileStream is used for the serialization.
Dim stream As New FileStream( _
"NewException.dat", FileMode.Create )
' Serialize the derived exception.
Try
Dim formatter As New SoapFormatter( Nothing, _
New StreamingContext( _
StreamingContextStates.File ) )
formatter.Serialize( stream, newExcept )
' Rewind the stream and deserialize the
' exception.
stream.Position = 0
Dim deserExcept As SecondLevelException = _
CType( formatter.Deserialize( stream ), _
SecondLevelException )
Console.WriteLine( vbCrLf & _
"Serialized the exception, and then " & _
"deserialized the resulting stream " & _
"into a " & vbCrLf & "new exception. " & _
"The deserialization changed the case " & _
"of certain properties:" & vbCrLf )
' Throw the deserialized exception again.
Throw deserExcept
Catch se As SerializationException
Console.WriteLine( "Failed to serialize: {0}", _
se.ToString( ) )
Finally
stream.Close( )
End Try
End Try
Catch ex As Exception
Console.WriteLine( "HelpLink: {0}", ex.HelpLink )
Console.WriteLine( "Source: {0}", ex.Source )
Console.WriteLine( )
Console.WriteLine( ex.ToString( ) )
End Try
End Sub
End Module
输出:
Forced a division by 0, caught the resulting exception, and created a derived exception: HelpLink: http://MSDN.Microsoft.com Source: Exception_Class_Samples Serialized the exception, and then deserialized the resulting stream into a new exception. The deserialization changed the case of certain properties: HelpLink: http://msdn.microsoft.com Source: EXCEPTION_CLASS_SAMPLES NDP_UE_VB.SecondLevelException: Forced a division by 0 and threw another exce ption. ---> System.DivideByZeroException: Attempted to divide by zero. at NDP_UE_VB.SerializationDemo.Main() --- End of inner exception stack trace --- at NDP_UE_VB.SerializationDemo.Main()
示例4: New
' Sample for Exception( String, Exception ) constructor.
Namespace NDP_UE_VB
' Derive an exception with a specifiable message and inner exception.
Class LogTableOverflowException
Inherits Exception
Private Const overflowMessage As String = _
"The log table has overflowed."
Public Sub New( )
MyBase.New( overflowMessage )
End Sub
Public Sub New( auxMessage As String )
MyBase.New( String.Format( "{0} - {1}", _
overflowMessage, auxMessage ) )
End Sub
Public Sub New( auxMessage As String, inner As Exception )
MyBase.New( String.Format( "{0} - {1}", _
overflowMessage, auxMessage ), inner )
End Sub
End Class
Class LogTable
Public Sub New( numElements As Integer )
logArea = New String( numElements ) { }
elemInUse = 0
End Sub
Protected logArea( ) As String
Protected elemInUse As Integer
' The AddRecord method throws a derived exception
' if the array bounds exception is caught.
Public Function AddRecord( newRecord As String ) As Integer
Try
Dim curElement as Integer = elemInUse
logArea( elemInUse ) = newRecord
elemInUse += 1
Return curElement
Catch ex As Exception
Throw New LogTableOverflowException( String.Format( _
"Record ""{0}"" was not logged.", newRecord ), ex )
End Try
End Function ' AddRecord
End Class
Module OverflowDemo
' Create a log table and force an overflow.
Sub Main()
Dim log As New LogTable(4)
Console.WriteLine( _
"This example of the Exception( String, Exception )" & _
vbCrLf & "constructor generates the following output." )
Console.WriteLine( vbCrLf & _
"Example of a derived exception " & vbCrLf & _
"that references an inner exception:" & vbCrLf )
Try
Dim count As Integer = 0
Do
log.AddRecord( _
String.Format( _
"Log record number {0}", count ) )
count += 1
Loop
Catch ex As Exception
Console.WriteLine( ex.ToString( ) )
End Try
End Sub
End Module ' OverflowDemo
End Namespace ' NDP_UE_VB
' This example of the Exception( String, Exception )
输出:
Example of a derived exception that references an inner exception: NDP_UE_VB.LogTableOverflowException: The log table has overflowed. - Record " Log record number 5" was not logged. ---> System.IndexOutOfRangeException: In dex was outside the bounds of the array. at NDP_UE_VB.LogTable.AddRecord(String newRecord) --- End of inner exception stack trace --- at NDP_UE_VB.LogTable.AddRecord(String newRecord) at NDP_UE_VB.OverflowDemo.Main()