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VB.NET Point构造函数代码示例

本文整理汇总了VB.NET中System.Drawing.Point.Point构造函数的典型用法代码示例。如果您正苦于以下问题:VB.NET Point构造函数的具体用法?VB.NET Point怎么用?VB.NET Point使用的例子?那么恭喜您, 这里精选的构造函数代码示例或许可以为您提供帮助。您也可以进一步了解该构造函数所在System.Drawing.Point的用法示例。

在下文中一共展示了Point构造函数的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的VB.NET代码示例。

示例1: Point

Private Sub Button1_Click(ByVal sender As System.Object, _
    ByVal e As System.EventArgs) Handles Button1.Click

    ' Construct a new Point with integers.
    Dim Point1 As New Point(100, 100)

    ' Create a Graphics object.
    Dim formGraphics As Graphics = Me.CreateGraphics()

    ' Construct another Point, this time using a Size.
    Dim Point2 As New Point(New Size(100, 100))

    ' Call the equality operator to see if the points are equal,  
    ' and if so print out their x and y values.
    If (Point.op_Equality(Point1, Point2)) Then
        formGraphics.DrawString(String.Format("Point1.X: " & _
            "{0},Point2.X: {1}, Point1.Y: {2}, Point2.Y {3}", _
            New Object() {Point1.X, Point2.X, Point1.Y, Point2.Y}), _
            Me.Font, Brushes.Black, New PointF(10, 70))
    End If

End Sub
开发者ID:VB.NET开发者,项目名称:System.Drawing,代码行数:22,代码来源:Point


示例2: Size

Private Sub InitializeLabel1()

    ' Set a border.
    Label1.BorderStyle = BorderStyle.FixedSingle

    ' Set the size, constructing a size from two integers.
    Label1.Size = New Size(100, 50)

    ' Set the location, constructing a point from a 32-bit integer
    ' (using hexadecimal).
    Label1.Location = New Point(&H280028)

    ' Set and align the text on the lower-right side of the label.
    Label1.TextAlign = ContentAlignment.BottomRight
    Label1.Text = "Bottom Right Alignment"
End Sub
开发者ID:VB.NET开发者,项目名称:System.Drawing,代码行数:16,代码来源:Point



注:本文中的System.Drawing.Point.Point构造函数示例整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。